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10.2: An Integral

Last updated

Aug 8, 2022
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- 10.1: Introduction
- 10.3: The Rocket Equation

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So that we don't get bogged down later with an integral that is going to crop up, see if you can do the following integration:

$\int\ln(a-bt)dt \nonumber$

You should get $-t-\frac{1}{b}(a-bt)\ln(a-bt)+$ constant.

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