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4.5: Conductors in Parallel

Last updated

Mar 5, 2022
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- 4.4: Resistors in Series
- 4.6: Dissipation of Energy

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IV.3.png
$\text{FIGURE IV.3}$

$G=G_1+G_2+G_3.\label{4.5.1}$

That is to say $\frac{1}{R} = \frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}.\label{4.5.2}$

The potential difference is the same across each. The current is greatest through the largest conductance – i.e. through the smallest resistance.

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