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Physics LibreTexts

4.5: Conductors in Parallel

  • Page ID
    5435


  • \(\text{FIGURE IV.3}\)

    \[G=G_1+G_2+G_3.\label{4.5.1}\]

    That is to say \[\frac{1}{R} = \frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}.\label{4.5.2}\]

    The potential difference is the same across each. The current is greatest through the largest conductance – i.e. through the smallest resistance.