6.2.1: Electromotive Force and Internal Resistance

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Apr 10, 2025
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- 6.2: Electromotive Force
- 6.3: Resistors in Series and Parallel

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The reader is reminded of the following definition from section 4.1:

Definition. The potential difference across the poles of a cell when no current is being taken from it is called the electromotive force (EMF) of the cell.

I shall use the symbol E for EMF.

Question. A 4 $\Omega$ resistance is connected across a cell of EMF 2 V. What current flows?

The immediate answer is 0.5 A – but this is likely to be wrong. The reason is that a cell has a resistance of its own – its internal resistance. The internal resistance of a lead-acid cell is typically quite small, but most dry cells have an appreciable internal resistance. If the external resistance is $R$ and the internal resistance is $r$ , the total resistance of the circuit is $R + r$ , so that the current that flows is E $/(R + r)$ .

Whenever a current is taken from a cell (or battery) the potential difference across its poles drops to a value less than its EMF. We can think of a cell as an EMF in series with an internal resistance:

$\text{FIGURE IV.4}$

If we take the point A as having zero potential, we see that the potential of the point B will be E - $Ir$ , and this, then, is the potential difference across the poles of the cell when a current $I$ is being taken from it.

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Show that this can also be written as $\frac{ER}{R+r}$ .

Show that this can also be written as ERR+r\frac{ER}{R+r}.

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Show that this can also be written as $\frac{ER}{R+r}$ .