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Physics LibreTexts

23.5: Examples

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Example 23.5.1

Motion in a horizontal circle.

Solution

Suppose you spin a mass m in a horizontal circle of radius r over your head; then the centripetal force (the tension in the string) is mv2/r, where v is the speed of the mass.

Assume there is no gravity present; then what happens if the string suddenly breaks? Then the mass will immediately move in a straight line tangent to the circle.

Example 23.5.2

Motion in a vertical circle.

Solution

If you spin a bucket of water in a circle in a vertical plane (Fig. 23.5.1, then (if you're spinning it fast enough) the centrifugal force (i.e. inertia) will keep the water in the bucket. How fast must you spin the bucket?

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Figure 23.5.1: A bucket of water being spun in a vertical circle. Inertia (sometimes thought of as a fictitious "centrifugal force") keeps the water in the bucket, even when upside-down. (Ref. [18]).

At top of the swing (when the string is vertical and the bucket is upside-down), the outward centrifugal force mv2/r must be greater than or equal to the weight of the water mg; so the minimum speed v of the bucket is given by

mv2r=mg

or

v=gr

The time T required for the bucket to make one complete circle (called the period of the motion) is then

T=2πrv=2πrgr

or

T=2πrg

For example, if the bucket is swung in a circle of radius 0.8 meters, this formula gives a period of 1.80 seconds; in other words, if you swing the bucket in a vertical circle at a constant speed so that it completes each circle in not more that 1.80 seconds, the water will stay in the bucket, even at the top of the swing.


23.5: Examples is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by LibreTexts.

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