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42.4: The Vertical Spring

Last updated

Aug 8, 2024
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- 42.3: Frequency and Period
- 42.5: Mass on a Spring

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If a horizontal mass on a spring is turned to a vertical position, then the spring is stretched by an amount $x_{0}=m g / k$ , giving it a new equilibrium position. For the vertical spring, the potential energy is still given by $U=\frac{1}{2} k x^{2}$ , but $x$ in this case refers to the distance from the original (horizontal) equilibrium position.

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