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- https://phys.libretexts.org/Courses/Prince_Georges_Community_College/PHY_1030%3A_General_Physics_I/05%3A_Uniform_Circular_Motion_and_Gravitation/5.9%3A_Angular_vs._Linear_QuantitiesThe familiar linear vector quantities such as velocity and momentum have analogous angular quantities used to describe circular motion.
- https://phys.libretexts.org/Courses/Gettysburg_College/Gettysburg_College_Physics_for_Physics_Majors/06%3A_C6)_Conservation_of_Angular_Momentum_I/6.03%3A_ExamplesIn the absence of external torques, a system’s total angular momentum is conserved. The angular velocity is inversely proportional to the moment of inertia, so if the moment of inertia decreases, the ...In the absence of external torques, a system’s total angular momentum is conserved. The angular velocity is inversely proportional to the moment of inertia, so if the moment of inertia decreases, the angular velocity must increase to conserve angular momentum. Systems containing both point particles and rigid bodies can be analyzed using conservation of angular momentum. The angular momentum of all bodies in the system must be taken about a common axis.
- https://phys.libretexts.org/Bookshelves/Classical_Mechanics/Variational_Principles_in_Classical_Mechanics_(Cline)/02%3A_Review_of_Newtonian_Mechanics/2.09%3A_Angular_Momentum_of_a_Many-Body_SystemFor a many-body system it is possible to separate the angular momentum into two components. One component is the angular momentum about the center of mass and the other component is the angular motion...For a many-body system it is possible to separate the angular momentum into two components. One component is the angular momentum about the center of mass and the other component is the angular motion of the center of mass about the origin of the coordinate system. This separation is done by describing the angular momentum of a many-body system using a position vector with respect to the center of mass plus the vector location of the center of mass.
- https://phys.libretexts.org/Courses/Joliet_Junior_College/Physics_201_-_Fall_2019v2/Book%3A_Custom_Physics_textbook_for_JJC/11%3A_Rotational_Kinematics_Angular_Momentum_and_Energy/11.20%3A_Angular_MomentumThe angular momentum of a single particle about a designated origin is the vector product of the position vector in the given coordinate system and the particle’s linear momentum. The net torque on a ...The angular momentum of a single particle about a designated origin is the vector product of the position vector in the given coordinate system and the particle’s linear momentum. The net torque on a system about a given origin is the time derivative of the angular momentum about that origin. A rigid rotating body has angular momentum directed along the axis of rotation.
- https://phys.libretexts.org/Courses/Berea_College/Introductory_Physics%3A_Berea_College/12%3A_Rotational_Energy_and_Momentum/12.03%3A_Angular_MomentumIn this section, we show that we can define a quantity called “angular momentum” as the rotational equivalent of the linear momentum.
- https://phys.libretexts.org/Bookshelves/Classical_Mechanics/Classical_Mechanics_(Tatum)/03%3A_Systems_of_Particles/3.07%3A_Angular_Momentum\[ \begin{align*} \textbf{L} &= \sum \textbf{r}_{i}\times \textbf{p}_{i} = \sum m_{i}(\textbf{r}_{i}\times \textbf{v}_{i}) = \sum m_{i}(\overline{\textbf{r}} + \textbf{r}_{i}^{\prime})\times(\overline...\[ \begin{align*} \textbf{L} &= \sum \textbf{r}_{i}\times \textbf{p}_{i} = \sum m_{i}(\textbf{r}_{i}\times \textbf{v}_{i}) = \sum m_{i}(\overline{\textbf{r}} + \textbf{r}_{i}^{\prime})\times(\overline{\textbf{v}} + \textbf{v}_{i}^{\prime}) \\[5pt] &=(\overline{\textbf{r}}\times \overline{\textbf{v}})\sum m_{i} + \overline{\textbf{r}}\times \sum m_{i}\textbf{v}_{i}^{\prime} + (\sum m_{i}\textbf{r}_{i}^{\prime}) \times \overline{\textbf{v}} + \sum \textbf{r}_{i}^{\prime} \times \textbf{p}_{i}^{\p…
- https://phys.libretexts.org/Courses/Joliet_Junior_College/Physics_201_-_Fall_2019/Book%3A_Physics_(Boundless)/10%3A_Rotational_Kinematics_Angular_Momentum_and_Energy/10.09%3A_Conservation_of_Angular_MomentumThe law of conservation of angular momentum states that when no external torque acts on an object, no change of angular momentum will occur.
- https://phys.libretexts.org/Bookshelves/University_Physics/Physics_(Boundless)/9%3A_Rotational_Kinematics_Angular_Momentum_and_Energy/9.7%3A_Vector_Nature_of_Rotational_KinematicsThe direction of angular quantities, such as angular velocity and angular momentum, is determined by using the right hand rule.
- https://phys.libretexts.org/Bookshelves/University_Physics/Book%3A_Introductory_Physics_-_Building_Models_to_Describe_Our_World_(Martin_Neary_Rinaldo_and_Woodman)/12%3A_Rotational_Energy_and_Momentum/12.03%3A_Angular_MomentumIn this section, we show that we can define a quantity called “angular momentum” as the rotational equivalent of the linear momentum.
- https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/09%3A_Momentum/9.09%3A_Angular_MomentumWe must include the Mars rock in the calculation of the moment of inertia, so we have \[I_{Total} = I_{R} + I_{F} + I_{MR} = 3.17\; kg\; \cdotp m^{2}\] and \[L = I \omega = (3.17\; kg\; \cdotp m^{2})(...We must include the Mars rock in the calculation of the moment of inertia, so we have \[I_{Total} = I_{R} + I_{F} + I_{MR} = 3.17\; kg\; \cdotp m^{2}\] and \[L = I \omega = (3.17\; kg\; \cdotp m^{2})(0.1 \pi\; rad/s) = 0.32 \pi\; kg\; \cdotp m^{2}/s \ldotp\] Now the angular momentum vector is directed into the page in the \(- \hat{k}\) direction, by the right-hand rule, since the robot arm is now rotating clockwise.
- https://phys.libretexts.org/Bookshelves/University_Physics/Physics_(Boundless)/9%3A_Rotational_Kinematics_Angular_Momentum_and_Energy/9.6%3A_Conservation_of_Angular_MomentumThe law of conservation of angular momentum states that when no external torque acts on an object, no change of angular momentum will occur.