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- https://phys.libretexts.org/Bookshelves/University_Physics/University_Physics_I_-_Classical_Mechanics_(Gea-Banacloche)/12%3A_Waves_in_One_Dimension/12.01%3A_Traveling_WavesIf we think of the momentum of a volume element in the medium as being proportional to the product of the instantaneous density and velocity, we see that for this wave, which is traveling in the posit...If we think of the momentum of a volume element in the medium as being proportional to the product of the instantaneous density and velocity, we see that for this wave, which is traveling in the positive \(x\) direction, there is more “positive momentum” than “negative momentum” in the medium at any given time (of course, if the wave had been traveling in the opposite direction, the sign of \(v_{med}\) in Equation (\ref{eq:12.6}) would have been negative, and we would have found the opposite re…
- https://phys.libretexts.org/Courses/Prince_Georges_Community_College/General_Physics_I%3A_Classical_Mechanics/50%3A_Elasticity/50.05%3A_Volume_Stresswhere \(\Delta V=V-V_{0}\) is the change in volume, \(V_{0}\) is the original (unstressed) volume and \(V\) is the stressed volume. If the gas is compressed, then \(\Delta V\) is negative and the stra...where \(\Delta V=V-V_{0}\) is the change in volume, \(V_{0}\) is the original (unstressed) volume and \(V\) is the stressed volume. If the gas is compressed, then \(\Delta V\) is negative and the strain \(\varepsilon\) is positive; if the gas expands, then \(\Delta V\) is positive and the strain \(\varepsilon\) is negative. In the case of volume stress, the appropriate elastic modulus is the bulk modulus B. Since the elastic modulus is the ratio of the stress to the strain, we have
- https://phys.libretexts.org/Bookshelves/University_Physics/Mechanics_and_Relativity_(Idema)/09%3A_Waves/9.02%3A_The_Wave_EquationAs with all phenomena in classical mechanics, the motion of the particles in a wave, for instance the masses on springs in Figure 9.1.1, are governed by Newton’s laws of motion and the various force l...As with all phenomena in classical mechanics, the motion of the particles in a wave, for instance the masses on springs in Figure 9.1.1, are governed by Newton’s laws of motion and the various force laws. In this section we will use these laws to derive an equation of motion for the wave itself, which applies quite generally to wave phenomena.
- https://phys.libretexts.org/Courses/Joliet_Junior_College/Physics_201_-_Fall_2019v2/Book%3A_Custom_Physics_textbook_for_JJC/10%3A_Static_Equilibrium_Elasticity_and_Torque/10.04%3A_Stress_Strain_and_Elastic_Modulus_(Part_1)External forces on an object cause its deformation, which is a change in its size and shape. The strength of the forces that cause deformation is expressed by stress. The extent of deformation under s...External forces on an object cause its deformation, which is a change in its size and shape. The strength of the forces that cause deformation is expressed by stress. The extent of deformation under stress is expressed by strain, which is dimensionless. Tensile (or compressive) stress, which causes elongation (or shortening) of the object or medium and is due to external forces acting along only one direction perpendicular to the cross-section.
- https://phys.libretexts.org/Courses/Merrimack_College/Conservation_Laws_Newton's_Laws_and_Kinematics_version_2.0/24%3A_Waves_in_One_Dimension/24.01%3A_Traveling_WavesIf we think of the momentum of a volume element in the medium as being proportional to the product of the instantaneous density and velocity, we see that for this wave, which is traveling in the posit...If we think of the momentum of a volume element in the medium as being proportional to the product of the instantaneous density and velocity, we see that for this wave, which is traveling in the positive \(x\) direction, there is more “positive momentum” than “negative momentum” in the medium at any given time (of course, if the wave had been traveling in the opposite direction, the sign of \(v_{med}\) in Equation (\ref{eq:12.6}) would have been negative, and we would have found the opposite re…
- https://phys.libretexts.org/Bookshelves/University_Physics/University_Physics_(OpenStax)/Book%3A_University_Physics_I_-_Mechanics_Sound_Oscillations_and_Waves_(OpenStax)/12%3A_Static_Equilibrium_and_Elasticity/12.04%3A_Stress_Strain_and_Elastic_Modulus_(Part_1)External forces on an object cause its deformation, which is a change in its size and shape. The strength of the forces that cause deformation is expressed by stress. The extent of deformation under s...External forces on an object cause its deformation, which is a change in its size and shape. The strength of the forces that cause deformation is expressed by stress. The extent of deformation under stress is expressed by strain, which is dimensionless. Tensile (or compressive) stress, which causes elongation (or shortening) of the object or medium and is due to external forces acting along only one direction perpendicular to the cross-section.
- https://phys.libretexts.org/Courses/Joliet_Junior_College/Physics_201_-_Fall_2019/Book%3A_Physics_(Boundless)/09%3A_Static_Equilibrium_Elasticity_and_Torque/9.1%3A_Static_Equilibrium_and_Elasticity/Stress_Strain_and_Elastic_Modulus_(Part_1)External forces on an object cause its deformation, which is a change in its size and shape. The strength of the forces that cause deformation is expressed by stress. The extent of deformation under s...External forces on an object cause its deformation, which is a change in its size and shape. The strength of the forces that cause deformation is expressed by stress. The extent of deformation under stress is expressed by strain, which is dimensionless. Tensile (or compressive) stress, which causes elongation (or shortening) of the object or medium and is due to external forces acting along only one direction perpendicular to the cross-section.
- https://phys.libretexts.org/Bookshelves/Classical_Mechanics/Classical_Mechanics_(Dourmashkin)/27%3A_Static_Fluids/27.5%3A_Compressibility_of_a_FluidWhen the pressure is uniform on all sides of an object in a fluid, the pressure will squeeze the object resulting in a smaller volume. When we increase the pressure by \(ΔP\) on a material of volume \...When the pressure is uniform on all sides of an object in a fluid, the pressure will squeeze the object resulting in a smaller volume. When we increase the pressure by \(ΔP\) on a material of volume \(v_{o}\), then the volume of the material will change by \(ΔV < 0\) and consequently the density of the material will also change. Determine the percentage decrease in a fixed volume of water at a depth of 4 km where the pressure difference is 40 Mpa, with respect to sea level.
- https://phys.libretexts.org/Courses/Prince_Georges_Community_College/General_Physics_I%3A_Classical_Mechanics/50%3A_Elasticity/50.01%3A_Introduction_to_Elasticitywhere \(\sigma\) is the stress, \(\varepsilon\) is the strain, and \(E\) is the elastic modulus, which takes the place of the spring constant in Hooke's law. In Eq. \(\PageIndex{1}\), the stress \(\si...where \(\sigma\) is the stress, \(\varepsilon\) is the strain, and \(E\) is the elastic modulus, which takes the place of the spring constant in Hooke's law. In Eq. \(\PageIndex{1}\), the stress \(\sigma\) and elastic modulus \(E\) both have units of \(\mathrm{N} / \mathrm{m}^{2}\); the strain \(\varepsilon\) is dimensionless. In all cases, the stress \(\sigma\) is defined as the force \(F\) applied to the body, divided by the area \(A\) over which the force acts:
