The price for gaining this multiplication of force is that the piston on the left must be moved through a greater distance than the object on the right will be raised. To find the distance \(d_{1}\) t...The price for gaining this multiplication of force is that the piston on the left must be moved through a greater distance than the object on the right will be raised. To find the distance \(d_{1}\) through which the piston on the left must be moved in order to lift the object on the right a distance \(d_{2}\), we note that the liquid is essentially incompressible; therefore the volume change on the left must equal the volume change on the right:
