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11.5: Magnetic Force on a Current-Carrying Conductor
https://phys.libretexts.org/Bookshelves/University_Physics/University_Physics_(OpenStax)/University_Physics_II_-_Thermodynamics_Electricity_and_Magnetism_(OpenStax)/11%3A_Magnetic_Forces_and_Fields/11.05%3A_Magnetic_Force_on_a_Current-Carrying_Conductor
Moving charges experience a force in a magnetic field. If these moving charges are in a wire—that is, if the wire is carrying a current—the wire should also experience a force. However, before we disc...Moving charges experience a force in a magnetic field. If these moving charges are in a wire—that is, if the wire is carrying a current—the wire should also experience a force. However, before we discuss the force exerted on a current by a magnetic field, we first examine the magnetic field generated by an electric current. We are studying two separate effects here that interact closely: A current-carrying wire generates a magnetic field and the magnetic field exerts a force on the wire.
6.3: Magnetic Fields and Lines
https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_II_(2212)/06%3A_Sources_of_Magnetism_Magnetic_Forces_and_Fields/6.03%3A_Magnetic_Fields_and_Lines
To calculate the force, we use the given charge, velocity, and magnetic field and the definition of the magnetic force in cross-product form to calculate: \[\vec{F} = q\vec{v} \times \vec{B} = (3.2 \t...To calculate the force, we use the given charge, velocity, and magnetic field and the definition of the magnetic force in cross-product form to calculate: $\vec{F} = q\vec{v} \times \vec{B} = (3.2 \times 10^{-19} C)((2.0 \hat{i} - 3.0 \hat{j} + 1.0 \hat{k}) \times 10^4 m/s) \times (1.5 \, T \hat{k})$ $(-14.4 \hat{i} - 9.6 \hat{j}) \times 10^{-15}N.$ This solution can be rewritten in terms of a magnitude and angle in the xy-plane: \[|\vec{F}| = \sqrt{F_x^2 + F_y^2} = \sqrt{(-14.4)^2 + (-9.6)…
8.8: Magnetic Force on a Current-Carrying Conductor
https://phys.libretexts.org/Courses/Kettering_University/Electricity_and_Magnetism_with_Applications_to_Amateur_Radio_and_Wireless_Technology/08%3A_The_Magnetic_Field/8.08%3A_Magnetic_Force_on_a_Current-Carrying_Conductor
Moving charges experience a force in a magnetic field. If these moving charges are in a wire—that is, if the wire is carrying a current—the wire should also experience a force. However, before we disc...Moving charges experience a force in a magnetic field. If these moving charges are in a wire—that is, if the wire is carrying a current—the wire should also experience a force. However, before we discuss the force exerted on a current by a magnetic field, we first examine the magnetic field generated by an electric current. We are studying two separate effects here that interact closely: A current-carrying wire generates a magnetic field and the magnetic field exerts a force on the wire.
22.7: Magnetic Force on a Current-Carrying Conductor
https://phys.libretexts.org/Bookshelves/College_Physics/College_Physics_1e_(OpenStax)/22%3A_Magnetism/22.07%3A_Magnetic_Force_on_a_Current-Carrying_Conductor
The magnetic force on current-carrying conductors is given by $F = \pi B sin \theta,$ where is the current, $l$ is the length of a straight conductor in a uniform magnetic field $B$ , and \...The magnetic force on current-carrying conductors is given by $F = \pi B sin \theta,$ where is the current, $l$ is the length of a straight conductor in a uniform magnetic field $B$ , and $\theta$ is the angle between $I$ and $B$ . The force follows RHR-1 with the thumb in the direction of $I$ .\
4.9: Common Forces - Magnetic Force
https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/04%3A_Forces/4.09%3A_Common_Forces_-_Magnetic_Force
To calculate the force, we use the given charge, velocity, and magnetic field and the definition of the magnetic force in cross-product form to calculate: \[\vec{F} = q\vec{v} \times \vec{B} = (3.2 \t...To calculate the force, we use the given charge, velocity, and magnetic field and the definition of the magnetic force in cross-product form to calculate: $\vec{F} = q\vec{v} \times \vec{B} = (3.2 \times 10^{-19} C)((2.0 \hat{i} - 3.0 \hat{j} + 1.0 \hat{k}) \times 10^4 m/s) \times (1.5 \, T \hat{k})$ $(-14.4 \hat{i} - 9.6 \hat{j}) \times 10^{-15}N.$ This solution can be rewritten in terms of a magnitude and angle in the xy-plane: \[|\vec{F}| = \sqrt{F_x^2 + F_y^2} = \sqrt{(-14.4)^2 + (-9.6)…
6.6: Magnetic Force on a Current-Carrying Conductor
https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_II_(2212)/06%3A_Sources_of_Magnetism_Magnetic_Forces_and_Fields/6.06%3A_Magnetic_Force_on_a_Current-Carrying_Conductor
A long, rigid wire lying along the y-axis carries a 5.0-A current flowing in the positive y-direction. (a) If a constant magnetic field of magnitude 0.30 T is directed along the positive x-axis, what ...A long, rigid wire lying along the y-axis carries a 5.0-A current flowing in the positive y-direction. (a) If a constant magnetic field of magnitude 0.30 T is directed along the positive x-axis, what is the magnetic force per unit length on the wire? (b) If a constant magnetic field of 0.30 T is directed 30 degrees from the +x-axis towards the +y-axis, what is the magnetic force per unit length on the wire?
12.4: Magnetic Force between Two Parallel Currents
https://phys.libretexts.org/Bookshelves/University_Physics/University_Physics_(OpenStax)/University_Physics_II_-_Thermodynamics_Electricity_and_Magnetism_(OpenStax)/12%3A_Sources_of_Magnetic_Fields/12.04%3A__Magnetic_Force_between_Two_Parallel_Currents
You might expect that two current-carrying wires generate significant forces between them, since ordinary currents produce magnetic fields and these fields exert significant forces on ordinary current...You might expect that two current-carrying wires generate significant forces between them, since ordinary currents produce magnetic fields and these fields exert significant forces on ordinary currents. But you might not expect that the force between wires is used to define the ampere. It might also surprise you to learn that this force has something to do with why large circuit breakers burn up when they attempt to interrupt large currents.
8.3: Magnetic Force between Two Parallel Currents
https://phys.libretexts.org/Courses/Grand_Rapids_Community_College/PH246_Calculus_Physics_II_(2025)/08%3A_Sources_of_Magnetic_Fields/8.03%3A__Magnetic_Force_between_Two_Parallel_Currents
You might expect that two current-carrying wires generate significant forces between them, since ordinary currents produce magnetic fields and these fields exert significant forces on ordinary current...You might expect that two current-carrying wires generate significant forces between them, since ordinary currents produce magnetic fields and these fields exert significant forces on ordinary currents. But you might not expect that the force between wires is used to define the ampere. It might also surprise you to learn that this force has something to do with why large circuit breakers burn up when they attempt to interrupt large currents.
22.10: Magnetic Force between Two Parallel Conductors
https://phys.libretexts.org/Bookshelves/College_Physics/College_Physics_1e_(OpenStax)/22%3A_Magnetism/22.10%3A_Magnetic_Force_between_Two_Parallel_Conductors
The force between two parallel currents $I_{1}$ and $I_{2}$ separated by a distance $r$ , has a magnitude per unit length given by $\frac{F}{l} = \frac{\mu_{0}I_{1}I_{2}}{2\pi r}.$ The force is...The force between two parallel currents $I_{1}$ and $I_{2}$ separated by a distance $r$ , has a magnitude per unit length given by $\frac{F}{l} = \frac{\mu_{0}I_{1}I_{2}}{2\pi r}.$ The force is attractive if the currents are in the same direction, repulsive if they are in opposite directions.
8.4: Magnetic Force between Two Parallel Currents
https://phys.libretexts.org/Courses/Muhlenberg_College/Physics_122%3A_General_Physics_II_(Collett)/08%3A_Sources_of_Magnetic_Fields/8.04%3A__Magnetic_Force_between_Two_Parallel_Currents
You might expect that two current-carrying wires generate significant forces between them, since ordinary currents produce magnetic fields and these fields exert significant forces on ordinary current...You might expect that two current-carrying wires generate significant forces between them, since ordinary currents produce magnetic fields and these fields exert significant forces on ordinary currents. But you might not expect that the force between wires is used to define the ampere. It might also surprise you to learn that this force has something to do with why large circuit breakers burn up when they attempt to interrupt large currents.
9.5: Magnetic Field Strength- Force on a Moving Charge in a Magnetic Field
https://phys.libretexts.org/Courses/Skyline/Survey_of_Physics/09%3A_Magnetism/9.05%3A_Magnetic_Field_Strength-_Force_on_a_Moving_Charge_in_a_Magnetic_Field
Magnetic fields exert a force on a moving charge q. The SI unit for magnetic field strength B is the tesla (T). The direction of the force on a moving charge is given by right hand rule 1: Point the t...Magnetic fields exert a force on a moving charge q. The SI unit for magnetic field strength B is the tesla (T). The direction of the force on a moving charge is given by right hand rule 1: Point the thumb of the right hand in the direction of v, the fingers in the direction of B, and a perpendicular to the palm points in the direction of F. The force is perpendicular to the plane formed by $mathbf{v}$ and \mathbf{B}.

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