# 5.8.8: Hollow Spherical Shell

- Page ID
- 8152

[ "article:topic", "authorname:tatumj", "showtoc:no" ]

*Outside* the sphere, the field and the potential are just as if all the mass were concentrated at a point in the centre. The potential, then, outside the sphere, is just \(−GM/r\). *Inside* the sphere, the field is zero and therefore the potential is uniform and is equal to the potential at the surface, which is \(−GM/a\). The reader should draw a graph of the potential as a function of distance from centre of the sphere. There is a discontinuity in the slope of the potential (and hence in the field) at the surface.