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# 4.7: Electromotive Force and Internal Resistance

[ "article:topic", "authorname:tatumj", "showtoc:no" ]

The reader is reminded of the following definition from section 4.1:

Definition.  The potential difference across the poles of a cell when no current is being taken from it is called the electromotive force (EMF) of the cell.

I shall use the symbol E for EMF.

Question.  A 4 $$\Omega$$ resistance is connected across a cell of EMF 2 V.  What current flows?

The immediate answer is 0.5 A – but this is likely to be wrong.  The reason is that a cell has a resistance of its own – its internal resistance.   The internal resistance of a lead-acid cell is typically quite small, but most dry cells have an appreciable internal resistance.  If the external resistance is $$R$$ and the internal resistance is $$r$$, the total resistance of the circuit is $$R + r$$, so that the current that flows is E$$/(R + r)$$.

Whenever a current is taken from a cell (or battery) the potential difference across its poles drops to a value less than its EMF.  We can think of a cell as an EMF in series with an internal resistance:

$$\text{FIGURE IV.4}$$

If we take the point A as having zero potential, we see that the potential of the point B will be E  -  $$Ir$$, and this, then, is the potential difference across the poles of the cell when a current $$I$$ is being taken from it.

Exercise

Show that this can also be written as $$\frac{ER}{R+r}$$.