15.15: RLC Series Circuits with AC (Q15.3.3)
- Page ID
- 51502
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A resistor and capacitor are connected in series across an ac generator. The emf of the generator is given by \(\displaystyle v(t)=V0cosωt,\) where \(\displaystyle V0=120V, ω=120πrad/s, R=400Ω,\) and \(\displaystyle C=4.0μF\).
- What is the impedance of the circuit?
- What is the amplitude of the current through the resistor?
- Write an expression for the current through the resistor.
- Write expressions representing the voltages across the resistor and across the capacitor.
Text Question
A resistor and capacitor are connected in series across an ac generator. The emf of the generator is given by \(\displaystyle v(t)=V0cosωt,\) where \(\displaystyle V0=120V, ω=120πrad/s, R=400Ω,\) and \(\displaystyle C=4.0μF\).
- What is the impedance of the circuit?
- What is the amplitude of the current through the resistor?
- Write an expression for the current through the resistor.
- Write expressions representing the voltages across the resistor and across the capacitor.
A11YQuestion
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Answer
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Solution
a. \(\displaystyle 770Ω\);
b. 0.16 A;
c. \(\displaystyle I=(0.16A)cos(120πt)\);
d. \(\displaystyle v_R=120cos(120πt); v_C=120cos(120πt−π/2)\)
Hint
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Link
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Notes
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