19.2: The Circulant Matrix- Nature of its Eigenstates
- Page ID
- 29520
The matrix we’ve constructed above has a very special property: each row is identical to the preceding row with the elements moved over one place, that is, it has the form
\begin{equation}
\left(\begin{array}{llll}
c_{0} & c_{1} & c_{2} & c_{3} \\
c_{3} & c_{0} & c_{1} & c_{2} \\
c_{2} & c_{3} & c_{0} & c_{1} \\
c_{1} & c_{2} & c_{3} & c_{0}
\end{array}\right)
\end{equation}
Such matrices are called circulants, and their properties are well known. In particular, we’ll show that the eigenvectors have the form \(\left(1, \omega_{j}, \omega_{j}^{2}, \omega_{j}^{3}, \ldots, \omega_{j}^{N-1}\right)^{T}\) where \(\omega_{j}^{N}=1\).
Recall the roots of the equation \(z^{N}=1\) are N points equally spaced around the unit circle, \begin{equation}
e^{2 \pi i n / N}, n=0,1,2, \ldots N-1
\end{equation}
The standard mathematical notation is to label these points \(\begin{equation}
1, \omega_{1}, \omega_{2}, \omega_{3}, \ldots, \omega_{N-1}
\end{equation}\) as shown in the figure, but notice that \(\omega_{j}=\omega_{1}^{j}\)