5.6: Capacitors in Series
- Page ID
- 5443
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\(\text{FIGURE V.6}\)
The charge is the same on each, and the potential difference across the system is the sum of the potential differences across the individual capacitances. Hence
\[\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}+\dfrac{1}{C_3}.\label{5.6.1}\]