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# 5.6: Capacitors in Series


$$\text{FIGURE V.6}$$

The charge is the same on each, and the potential difference across the system is the sum of the potential differences across the individual capacitances. Hence

$\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}+\dfrac{1}{C_3}.\label{5.6.1}$

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