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Physics LibreTexts

10.6: Common Fourier Transforms

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To accumulate more intuition about Fourier transforms, let us examine the Fourier transforms of some interesting functions. We will just state the results; the calculations are left as exercises.

Damped waves

We saw in Section 10.2 that an exponentially decay function with decay constant ηR+ has the following Fourier transform: f(x)={eηx,x00,x<0,FTF(k)=ikiη.

Observe that F(k) is given by a simple algebraic formula. If we “extend” the domain of k to complex values, F(k) corresponds to an analytic function with a simple pole in the upper half of the complex plane, at k=iη.

Next, consider a decaying wave with wave-number qR and decay constant ηR+. The Fourier transform is a function with a simple pole at q+iη: f(x)={ei(q+iη)x,x00,x<0.FTF(k)=ik(q+iη).

On the other hand, consider a wave that grows exponentially with x for x<0, and is zero for x>0. The Fourier transform is a function with a simple pole in the lower half-plane: f(x)={0,x0ei(qiη)x,x<0.FTF(k)=ik(qiη).

From these examples, we see that oscillations and amplification/decay in f(x) are related to the existence of poles in the algebraic expression for F(k). The real part of the pole position gives the wave-number of the oscillation, and the distance from the pole to the real axis gives the amplification or decay constant. A decaying signal produces a pole in the upper half-plane, while a signal that is increasing exponentially with x produces a pole in the lower half-plane. In both cases, if we plot the Fourier spectrum of |F(k)|2 versus real k, the result is a Lorentzian peak centered at k=q, with width 2η.

Gaussian wave-packets

Consider a function with a decay envelope given by a Gaussian function: f(x)=eiqxeγx2,whereqC,γR.

This is called a Gaussian wave-packet. The width of the envelope is usually characterized by the Gaussian function’s standard deviation, which is where the curve reaches e1/2 times its peak value. In this case, the standard deviation is Δx=1/2γ.

We will show that f(x) has the following Fourier transform: F(k)=πγe(kq)24γ.

To derive this result, we perform the Fourier integral as follows: F(k)=dxeikxf(x)=dxexp{i(kq)xγx2}.

In the integrand, the expression inside the exponential is quadratic in x. We complete the square: F(k)=dxexp{γ(x+i(kq)2γ)2+γ(i(kq)2γ)2}=exp{(kq)24γ}dxexp{γ(x+i(kq)2γ)2}.
The remaining integral is the Gaussian integral with a constant imaginary shift in x. By shifting the integration variable, one can show that this is equal the standard Gaussian integral, π/γ; the details are left as an exercise. We thus arrive at the result stated above.

The Fourier spectrum, |F(k)|2, is a Gaussian function with standard deviation Δk=12(1/2γ)=γ.

clipboard_ebe64484c1b9f9aea2652298a2365dc49.png
Figure 10.6.1

Once again, the Fourier spectrum is peaked at a value of k corresponding to the wave-number of the underlying sinusoidal wave in f(x), and a stronger (weaker) decay in f(x) leads to a broader (narrower) Fourier spectrum. These features can be observed in the plot above.


This page titled 10.6: Common Fourier Transforms is shared under a CC BY-SA 4.0 license and was authored, remixed, and/or curated by Y. D. Chong via source content that was edited to the style and standards of the LibreTexts platform.

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