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Physics LibreTexts

12.3: The Exchange Operator

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The exchange operator, notated here by ˆP12, just exchanges particle 1 for particle 2. In order to satisfy the conditions described in Section 12.1, a state composed of two indistinguishable particles (e.g. two electrons) must be an eigenstate of the exchange operator. Suppose that |ξ is such a state. This means that

ˆP12|ξ=c|ξ

where c is the eigenvalue. Suppose that we apply the exchange operator twice. What will happen? We should get back to the original state! We’ve just swapped the two particles back. Let’s apply this twice:

ˆP12ˆP12|ξ=ˆP12(c|ξ)=cˆP12|ξ=c2|ξ

If the result of applying this exchange operator twice must be the state we started with, then we must have c2=1. This is regular old fashioned squaring, not taking the absolute square. That c2=1 means that there are only two possibilities for the eigenvalue of the exchange operator working on a state of two indistinguishable particles: c=1 or c=1.


This page titled 12.3: The Exchange Operator is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by Pieter Kok via source content that was edited to the style and standards of the LibreTexts platform.

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