7.5: Equation of State
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The equation of state, as given by Equation 7.4.19, requires the computation of the grand canonical partition function. We will consider the case where the only conserved quantities are the Hamiltonian and the number of particles. The grand canonical partition function can then be written as
Z=∞∑N=0zNQN=1+∞∑N=1zNQNz=eβμ
where QN is the canonical partition for a fixed number of particles, given in Equation 7.4.12. The variable z=eβµ is called the fugacity. The easiest way to proceed to the equation of state is to consider an expansion of logZ in powers of z. This is known as the cumulant expansion and, explicitly, it takes the form
log[1+∞∑N=1zNQN]=1+∞∑n=1zNan
where the first few coefficients are easily worked out as
a1=Q1a2=Q2−12Q21a3=Q3−Q2Q1+13Q21
The Hamiltonian, for N particles, has the form
HN=∑ip2i2m+∑i<jV(xi,xj)+...
where we have included a general two-particle interaction and the ellipsis stands for possible 3-particle and higher interactions. For N=1 we just have the first term. The p-integrations factorize and, if V(xi,xj)=0, we get QN=QN1N!. All cumulants an vanish except for a1. We can explicitly obtain
a1=Q1=∫d3xid3pi(2πħ)3exp(−βp22m)=V(m2πβħ2)32
For Q2, we find
Q2=12!Q21V2∫d3x1d3x2e−βV(x1,x2)=Q212V∫d3xe−βV(x)
where, in the second line, we have taken the potential to depend only on the difference →x1−→x2 and carried out the integration over the center of mass coordinate. Thus
a2=Q212V∫d3x(1−e−βV(x))
Using the cumulant expansion to this order, we find logZ≈zQ1+z2a2 and the average number of particles in the volume V is given by
ˉN=1β∂∂μlogZ≈zQ1+z2a2
which can be solved for z as
zQ1≈ˉN−2a2ˉN2Q21+...
If we ignore the a2-term, this relation is the same as what we found in Equation 7.2.14, with the addition of the (2πħ)3 correction,
βμ=log[ˉNV(2πħ2mkT)]
Using Equation ??? (with the a2-term) back in logZ and the expression ??? for a2, we get
pVˉNkT≈[1+ˉNVB2+...]B2=12∫d3x(1−e−βV(x))
These formulae show explicitly the first correction to the ideal gas equation of state. The quantity B2 is a function of temperature; it is called the second virial coefficient and can be calculated, once a potential is known, by carrying out the integration. Even for complicated potentials it can be done, at least, numerically. As a simple example, consider a hard sphere approximation to the interatomic potential,
V(r)={∞r<r00r>r0
In this case the integral is easily done to obtain B2=(2πr303) This is independent of the temperature. One can consider more realistic potentials for better approximations to the equation of state.
The van der Waals equation, which we considered earlier, is, at best, a model for the equation of state incorporating some features of the interatomic forces. Here we have a more systematic way to calculate with realistic interatomic potentials. Nevertheless, there is a point of comparison which is interesting. If we expand the van der Waals equation in the form in Equation ???, it has B2=b−(akT); the term b is independent of the temperature. Comparing with the hard sphere repulsion at short distances, we see how something like the excluded volume effect can arise.
We have considered the first corrections due to the interatomic forces. More generally, the equation of state takes the form
pVˉNkT=[1+∞∑n=2(ˉNV)n−1Bn]
This is known as the virial expansion, with Bn referred to as the n-th virial coefficient. These are in general functions of the temperature; they can be calculated by continuing the cumulant expansion to higher order and doing the integrations needed for QN. In practice such a calculation becomes more and more difficult as N increases. This virial expansion in Equation ??? is in powers of the density ˉNV and integrations involving powers of e−βVint, where Vint is the potential energy of the interaction. Thus for low densities and interaction strengths small compared to kT, truncation of the series at some finite order is a good approximation. So only a few of the virial coefficients are usually calculated.
It is useful to calculate corrections to some of the other quantities as well. From the identification of ˉN in Equation ??? and from Equation 7.4.16, we can find the internal energy as
U=32ˉNkT+ˉN22V∫d3xV(x)e−βV(x)+...
In a similar way, the entropy is found to be
ˉS=ˉNk[52+logVˉN+32log(mkT2πħ2)+ˉN2V∫d3x(βV(x)e−βV(x)−1+e−βV(x))]
Since the number of pairs of particles is ≈N22, the correction to the internal energy is easily understood as an average of the potential energy. Also the first set of terms in the entropy reproduces the Sackur-Tetrode formula (7.2.25) for an ideal gas.