14.9: Problems
- Page ID
- 33183
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\(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)- An alternate way to modify the energy-momentum relation while maintaining relativistic invariance is with a “potential mass”, \(H(x)\): \[ E^{2}=p^{2} c^{2}+(m+H)^{2} c^{4}\]
If \(|H| \ll m \text { and } p^{2} \ll m^{2} c^{2}\), show how this equation may be approximated as \[ E=\text { something }+p^{2} /(2 m)\] and determine the form of “\(something\) ” in terms of \(H\). Is this theory distinguishable from the theory involving potential energy at nonrelativistic velocities?
- For a given channel length \(L\) and particle speed in Figure \(\PageIndex{1}\):, determine the possible values of potential momentum \(\pm Q\) in the two channels that result in destructive interference between the two parts of the particle wave.
- Show that equations (14.14) and (14.15) are indeed recovered from equations (14.12) and (14.13) when \(Q\) points in the \(y \) direction and is a function only of \(x\).
- Show that the force \(F\) = \(v\) × \(P\) is perpendicular to the velocity \(v\). Does this force do any work on the particle? Is this consistent with the fact that the force doesn’t change the particle’s kinetic energy?
- Show that the potential momentum illustrated in Figure \(\PageIndex{2}\): satisfies the Lorenz condition, assuming that \(U \) = 0. Would the Lorenz condition be satisfied in this case if \(Q\) depended only on \(x \) and pointed in the \(x\) direction?
- A mass \(m \) moves at non-relativistic speed around a circular track of radius \(R \) as shown in Figure \(\PageIndex{7}\):. The mass is subject to a potential momentum vector of magnitude \(Q \) pointing counterclockwise around the track.
- If the particle moves at speed \(v\), does it have a longer wavelength when it is moving clockwise or counterclockwise? Explain.
- Quantization of angular momentum is obtained by assuming that an integer number of wavelengths \(n \) fits into the circumference of the track. For given |\(n\) |, determine the speed of the mass (i) if it is moving clockwise (\(n < \) 0), and (ii) if it is moving counterclockwise (\(n > \) 0).
- Determine the kinetic energy of the mass as a function of \(n\).
- Suppose momentum were conserved for action at a distance in a particular reference frame between particles 1 cm apart as in the left panel of Figure \(\PageIndex{4}\): in the text. If you are moving at velocity 2 × 108 m s-1 relative to this reference frame, for how long a time interval is momentum apparently not conserved? Hint: The 1 cm interval is the invariant distance between the kinks in the world lines.
- An electron moving to the right at speed \(v \) collides with a positron (an antielectron) moving to the left at the same speed as shown in Figure \(\PageIndex{8}\):. The two particles annihilate, forming a virtual photon, which then decays into a proton-antiproton pair. The mass of the electron is \(m \) and the mass of the proton is \(M \) = 1830\(m\).
- What is the mass of the virtual photon? Hint: It is not 2\(m\). Why?
- What is the maximum possible lifetime of the virtual photon by the uncertainty principle?
- What is the minimum \(v \) the electron and positron need to have to make this reaction energetically possible? Hint: How much energy must exist in the proton-antiproton pair?
- A muon (mass \(m\) ) interacts with a proton as shown in Figure \(\PageIndex{9}\):, so that the velocity of the muon before the interaction is \(v\), while after the interaction it is \(-v / 2\), all in the \(x\) direction. The interaction is mediated by a single virtual photon. Assume that \(v \ll c\) for simplicity.
- What is the momentum of the photon?
- What is the energy of the photon?
- A photon with energy \(E \) and momentum \(E / c\) collides with an electron with momentum \(p=-E / c\) in the \(x \) direction and mass \(m\). The photon is absorbed, creating a virtual electron. Later the electron emits a photon in the \(x\) direction with energy \(E \) and momentum -\(E ∕ c\). (This process is called Compton scattering and is illustrated in Figure \(\PageIndex{10}\):.)
- Compute the energy of the electron before it absorbs the photon.
- Compute the mass of the virtual electron, and hence the maximum proper time it can exist before emitting a photon.
- Compute the velocity of the electron before it absorbs the photon.
- Using the above result, compute the energies of the incoming and outgoing photons in a frame of reference in which the electron is initially at rest. Hint: Using \(E_{\text {photon }}=\hbar \omega\) and the above velocity, use the Doppler shift formulas to get the photon frequencies, and hence energies in the new reference frame.
- The dispersion relation for a negative energy relativistic particle is \[\omega=-\left(k^{2} c^{2}+\mu^{2}\right)^{1 / 2}\]
Compute the group velocity of such a particle. Convert the result into an expression in terms of momentum rather than wavenumber. Compare this to the corresponding expression for a positive energy particle and relate it to Feynman’s explanation of negative energy states.
- The potential energy of a charged particle in a scalar electromagnetic potential \(ϕ\) is the charge times the scalar potential. The total energy of such a particle at rest is therefore \[ E=\pm m c^{2}+q \phi \]
where \(q \) is the charge on the particle and \(\pm m c^{2}\) is the rest energy, with the ± corresponding to positive and negative energy states. Assume that \(|q \phi| \ll m c^{2}\).
- Given that a particle with energy \(E<0\) is equivalent to the corresponding antiparticle with energy equal to \(-E>0\), what is the potential energy of the antiparticle?
- From this, what can you conclude about the charge on the antiparticle?
Hint: Recall that the total energy is always rest energy plus kinetic energy (zero in this case) plus potential energy.