1.3: Units
By the end of this section, you will be able to
- Identify the meaning of commonly used prefixes for units.
- Identify SI units associated with electricity and magnetism and their abbreviations.
The term “unit” refers to the measure used to express a physical quantity. For example, the mean radius of the Earth is about 6,371,000 meters; in this case the unit is the meter.
A number like “6,371,000” becomes a bit cumbersome to write, so it is common to use a prefix to modify the unit. For example, the radius of the Earth is more commonly said to be 6371 kilometers, where one kilometer is understood to mean 1000 meters. It is common practice to use prefixes, such as “kilo-,” that yield values in the range 0.001 to 10, 000. A list of standard prefixes appears in Table \(\PageIndex{1}\).
| Prefix | Multiply by: | Multiply by: |
|---|---|---|
| exa | \(\mathrm{E}\) | \(10^{18}\) |
| peta | \(\mathrm{P}\) | \(10^{15}\) |
| tera | \(\mathrm{T}\) | \(10^{12}\) |
| giga | \(\mathrm{G}\) | \(10^9\) |
| mega | \(\mathrm{M}\) | \(10^6\) |
| kil | \(\mathrm{k}\) | \(10^3\) |
| milli | \(\mathrm{m}\) | \(10^{−3}\) |
| micro | \(\mathrm{µ}\) | \(10^{−6}\) |
| nano | \(\mathrm{n}\) | \(10^{−9}\) |
| pico | \(\mathrm{p}\) | \(10^{−12}\) |
| femto | \(\mathrm{f}\) | \(10^{−15}\) |
| atto | \(\mathrm{a}\) | \(10^{−18}\) |
Writing out the names of units can also become tedious. For this reason, it is common to use standard abbreviations, e.g., “6731 km” as opposed to “6371 kilometers,” where “k” is the standard abbreviation for the prefix “kilo” and “m” is the standard abbreviation for “meter.” Table \(\PageIndex{2}\) shows a list of commonly used base units and their abbreviations.
| Unit | Abbreviation | Quantifies: |
|---|---|---|
| ampere | \(\mathrm{A}\) | electric current |
| coulomb | \(\mathrm{C}\) | electric charge |
| farad | \(\mathrm{F}\) | capacitance |
| henry | \(\mathrm{H}\) | inductance |
| hertz | \(\mathrm{Hz}\) | frequency |
| joule | \(\mathrm{J}\) | energy |
| meter | \(\mathrm{m}\) | distance |
| newton | \(\mathrm{N}\) | force |
| ohm | \(\mathrm{Ω}\) | resistance |
| second | \(\mathrm{s}\) | time |
| tesla | \(\mathrm{T}\) | magnetic flux density |
| volt | \(\mathrm{V}\) | electric potential |
| watt | \(\mathrm{W}\) | power |
| weber | \(\mathrm{Wb}\) | magnetic flux |
To avoid ambiguity, it is important to always indicate the units of a quantity, e.g., writing “6371 km” instead of “6371.” Failure to do so is a common source of error and misunderstanding. An example is the expression:
\[l = 3t \nonumber \]
where l is length and t is time. It could be that \(l\) is in meters and t is in seconds, in which case “3” really means “3 m/s”. However, if it is intended that \(l\) is in kilometers and \(t\) is in hours, then “3” really means “3 km/h” and the equation is literally different. To patch this up, one might write “\(l = 3t\) m/s”; however, note that this does not resolve the ambiguity we just identified – i.e., we still don’t know the units of the constant “3.” Alternatively, one might write “\(l = 3t\) where \(l\) is in meters and \(t\) is in seconds,” which is unambiguous but becomes quite awkward for more complicated expressions. A better solution is to write instead:
\[l = (3 \: \text{m/s})t \nonumber \]
or even better:
\[l = at \nonumber\]
where \(a = 3 \: \text{m/s}\) since this separates this issue of units from the perhaps more important fact that \(l\) is proportional to \(t\) and the constant of proportionality (\(a\)) is known.
The meter is the fundamental unit of length in the International System of Units, known by its French acronym “SI” and sometimes informally referred to as the “metric system.”
In this work, we will use SI units exclusively.
Although SI is probably the most popular for engineering use overall, other systems remain in common use. For example, the English system, where the radius of the Earth might alternatively be said to be about 3959 miles, continues to be used in various applications and, to a lesser or greater extent, in various regions of the world. An alternative system commonly used in physics and material science applications is the CGS (“centimeter-gram-second”) system. The CGS system is similar to SI but with some significant differences. For example, the base unit of energy in the CGS system is not the “joule,” but rather the “erg,” and the values of some physical constants become unitless. Therefore – once again – it is very important to include units whenever values are stated.
SI defines seven fundamental units from which all other units can be derived. These fundamental units are distance in meters (m), time in seconds (s), current in amperes (A), mass in kilograms (kg), temperature in kelvin (K), particle count in moles (mol), and luminosity in candela (cd). SI units for electromagnetic quantities, such as coulombs (C) for charge and volts (V) for electric potential, are derived from these fundamental units.
A frequently overlooked feature of units is their ability to assist in error-checking mathematical expressions. For example, the electric field intensity may be specified in volts per meter (V/m), so an expression for the electric field intensity that yields units of V/m is said to be “dimensionally correct” (but not necessarily correct), whereas an expression that cannot be reduced to units of V/m cannot be correct.
Additional Reading
- Wikipedia contributors. International System of Units [Internet]. Wikipedia, The Free Encyclopedia.
- Wikipedia contributors. Centimetre–gram–second system of units [Internet]. Wikipedia, The Free Encyclopedia.
Technician Exam Questions
To become an Amateur Radio operator at the introductory level in the United States, a person must pass the Technician licensing exam. This exam consists of 35 multiple-choice questions. The questions are drawn at random from a pool of questions over a distribution of topics. Selected questions from the current pool (valid for 2022‒26) are shown throughout the text.
Metric Prefixes
Relevant exam questions include: T5B01‒08, T5B12‒13, T5C07, T5C13.
T5B01. How many milliamperes is 1.5 amperes?
A. 15 milliamperes
B. 150 milliamperes
C. 1500 milliamperes
D. 15,000 milliamperes
- Answer
-
C. 1500 milliamperes. A current of 1 A is 1000 milliamperes, so 1.5 A is 1500 milliamperes.
[Beta Testing: Single Technician exam question from ADAPT (T5B01). It appears that you need to have an ADAPT account to access the question in the formative assignment.]
ADAPT \(\PageIndex{1}\)
[Beta Testing: Multiple Technician exam questions from ADAPT (T5B01-08, T5B12-13, T5C07, T5C13). It appears that you need have an ADAPT account to access these questions in a formative assignment.]
ADAPT \(\PageIndex{2}\)