Loading [MathJax]/jax/output/HTML-CSS/jax.js
Skip to main content
Library homepage
 

Text Color

Text Size

 

Margin Size

 

Font Type

Enable Dyslexic Font
Physics LibreTexts

5.3: Examples

( \newcommand{\kernel}{\mathrm{null}\,}\)

Whiteboard Problem 5.3.1: System Definitions

For each of the following sets of objects, define two systems each; one that is isolated and one that is not.  

  1. The Earth, Sun, and Moon.
  2. A football flying through the air, during the time after it is thrown and before it is caught. (you may ignore air resistance here)
  3. Two colliding carts, ignoring friction and air resistance.
  4. Two colliding carts, ignore air resistance but including the friction between the ground and the carts. 
Whiteboard Problem 5.3.2: Impulsive Shooter

wbC8-Figure1.pngA soccer player receives a pass in the air from a teammate and immediately fires the ball along the ground into the goal. The initial speed of the soccer ball is 15.0 m/s at an angle of 40.0 below the horizontal. The mass of the ball is 435 g.


 If this is David Beckham, he can get the shot moving with a speed of of 30.0 m/s, moving straight along the ground. What impulse (magnitude and direction) did his foot transfer to the soccer ball?

Whiteboard Problem 5.3.3: Impulsive Batter

BaseballHit.pngA baseball player is hitting a baseball as shown in the figure. The baseball has a mass of 145 g, and is traveling at the batter at a speed of 35 m/s (that's an 80-mph fastball). The baseball player can deliver an impulse of 5.5 kg m/s to the baseball when they hit it.

  1. The baseball player hits the ball at an angle of 15, as shown in the figure. How much impulse does the baseball player give to the ball in the x- and y-directions?
  2. What is the final speed of the ball?
  3. How much impulse was transferred to the player (through the bat) when they hit the ball?
Example 5.3.4: Collision, Center of Mass, and Recoil1

An 80-kg hockey player (call him player 1), moving at 3 m/s to the right, collides with a 90-kg player (player 2) who was moving at 2 m/s to the left. For a brief moment, they are stuck sliding together as they grab at each other.

  1. What is their joint velocity as they slide together?
  2. What was the velocity of their center of mass before and after the collision?

Solution

(a) Call the initial velocities v1i and v2i, the joint final velocity vf, and assume the two players are an isolated system for practical purposes. Then conservation of momentum reads

m1v1i+m2v2i=(m1+m2)vf.

Solving for the final velocity, we get

vf=m1v1i+m2v2im1+m2.

Substituting the values given, we get

vf=80×390×2170=0.353ms.

(b) According to Equation (3.3.3), the velocity of the center of mass, vcm, is just the same as what we just calculated (Equation ???) above). This makes sense: after the collision, if the players are moving together, their system’s center of mass has to be moving with them. Also, if the system is isolated, the center of mass velocity should be the same before and after the collision. So the answer is vcm = vf = 0.353 m/s.


1For a variation of this problem that studies the relative velocity of this system with respect to another frame, check out Example 3.5.2 in University Physics 1 - Classical Mechanics, by Gea-Banacloche.


This page titled 5.3: Examples is shared under a CC BY-SA 4.0 license and was authored, remixed, and/or curated by Christopher Duston, Merrimack College (University of Arkansas Libraries) via source content that was edited to the style and standards of the LibreTexts platform.

Support Center

How can we help?