Appendix E: Mathematical Formulas
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Quadratic formula
If ax2 + bx + c = 0, then x = −b±√b2−4ac2a
Table E1 - Geometry
Triangle of base b and height h | Area = 12bh | |
Circle of radius r | Circumference = 2πr | Area = πr2 |
Sphere of radius r | Surface Area = 2πr2 | Volume = 43πr3 |
Cylinder of radius r and height h | Area of curved surface = 2πrh | Volume = πr2h |
Trigonometry
Trigonometric Identities
- sin θ = 1cscθ
- cos θ = 1secθ
- tan θ = 1cotθ
- sin(90° − θ) = cos θ
- cos(90° − θ) = sin θ
- tan(90° − θ) = cot θ
- sin2 θ + cos2 θ = 1
- sec2 θ − tan2 θ = 1
- tan θ = sinθcosθ
- sin(α±β) = sin α cos β ± cos α sin β
- cos(α±β) = cos α cos β ∓ sin α sin β
- tan(α±β) = tanα±tanβ1∓tanαtanβ
- sin 2θ = 2sin θcos θ
- cos 2θ = cos2 θ − sin2 θ = 2 cos2 θ − 1 = 1 − 2 sin2 θ
- sin α + sin β = 2 sin12(α + β)cos12(α − β)
- cos α + cos β = 2 cos12(α + β)cos12(α − β)
Triangles
- Law of sines: asinα = bsinβ = csinγ
- Law of cosines: c2 = a2 + b2 − 2ab cos γ
- Pythagorean theorem: a2 + b2 = c2
Series expansions
- Binomial theorem: (a + b)n = an + nan-1b + n(n−1)an−2b22! + n(n−1)(n−2)an−3b33! + ⋯
- (1 ± x)n = 1 ± nx1!+n(n−1)x22!±⋯ (x2 < 1)
- (1 ± x)-n = 1 ∓ nx1!+n(n+1)x22!∓⋯ (x2 < 1)
- sin x = x - x33!+x55!−⋯
- cos x = 1 - x22!+x44!−⋯
- tan x = x + x33+2x515+⋯
- ex = 1 + x + x22!+⋯
- ln(1 + x) = x − 12x2+13x3−⋯ (|x| < 1)
Derivatives
- ddx[a f(x)] = a ddxf(x)
- ddx[f(x) + g(x)] = ddxf(x) + ddxg(x)
- ddx[f(x)g(x)] = f(x) ddxg(x) + g(x) ddxf(x)
- ddxf(u) = [dduf(u)]dudx
- ddxxm = mxm − 1
- ddxsin x = cos x
- ddxcos x = −sin x
- ddxtan x = sec2 x
- ddxcot x = −csc2 x
- ddxsec x = tan x sec x
- ddxcsc x = −cot x csc x
- ddxex = ex
- ddxln x = 1x
- ddxsin−1 x = 11−x2
- ddxcos−1 x = −11−x2
- ddxtan−1 x = −11+x2
Integrals
- ∫a f(x)dx = a ∫f(x)dx
- ∫[f(x) + g(x)]dx = ∫f(x)dx + ∫g(x)dx
- ∫xm dx = xm+1m+1 for (m ≠ −1) = ln x for (m = −1)
- ∫sin x dx = −cos x
- ∫cos x dx = sin x
- ∫tan x dx = ln|sec x|
- ∫sin2 (ax) dx = x2 − sin2ax4a
- ∫cos2 (ax) dx = x2 + sin2ax4a
- ∫sin (ax) cos (ax) dx = −cos2ax4a
- ∫eax dx = 1aeax
- ∫xeax dx = eaxa2(ax − 1)
- ∫ln ax dx = x ln ax − x
- ∫dxa2+x2 = 1atan−1 xa
- ∫dxa2−x2 = 12a ln|x+ax−a|
- ∫dx√a2+x2 = sinh−1 xa
- ∫dx√a2−x2 = sin−1 xa
- ∫√a2+x2 dx = x2√a2+x2+a22sinh−1xa
- ∫√a2−x2 dx = x2√a2−x2+a22sin−1xa
Contributors and Attributions
Samuel J. Ling (Truman State University), Jeff Sanny (Loyola Marymount University), and Bill Moebs with many contributing authors. This work is licensed by OpenStax University Physics under a Creative Commons Attribution License (by 4.0).