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7.1: The van der Waals system

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Equation of state

Recall the van der Waals equation of state,

(p+av2)(vb)=RT ,

where v=NAV/N is the molar volume. Solving for p(v,T), we have

p=RTvbav2.

Let us fix the temperature T and examine the function p(v). Clearly p(v) is a decreasing function of volume for v just above the minimum allowed value v=b, as well as for v. But is p(v) a monotonic function for all v[b,]?

We can answer this by computing the derivative,

(pv)T=2av3RT(vb)2.

Setting this expression to zero for finite v, we obtain the equation1

2abRT=u3(u1)2 ,

where uv/b is dimensionless. It is easy to see that the function f(u)=u3/(u1)2 has a unique minimum for u>1. Setting f(u)=0 yields u=3, and so fmin=f(3)=274. Thus, for T>Tc=8a/27bR, the LHS of Equation ??? lies below the minimum value of the RHS, and there is no solution. This means that p(v,T>Tc) is a monotonically decreasing function of v.

At T=Tc there is a saddle-node bifurcation. Setting vc=bu=3b and evaluating pc=p(vc,Tc), we have that the location of the critical point for the van der Waals system is

pc=a27b2,vc=3b,Tc=8a27bR.

For T<Tc, there are two solutions to Equation ???, corresponding to a local minimum and a local maximum of the function p(v). The locus of points in the (v,p) plane for which (p/v)T=0 is obtained by setting Equation ??? to zero and solving for T, then substituting this into Equation ???. The result is

p(v)=av22abv3.

Expressed in terms of dimensionless quantities ˉp=p/pc and ˉv=v/vc, this equation becomes

ˉp(ˉv)=3ˉv22ˉv3.

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Figure 7.1.1: Pressure versus molar volume for the van der Waals gas at temperatures in equal intervals from T=1.10Tc (red) to T=0.85Tc (blue). The purple curve is ˉp(ˉv).

Along the curve p=p(v), the isothermal compressibility, κT=1v(vp)T diverges, heralding a thermodynamic instability. To understand better, let us compute the free energy of the van der Waals system, F=ETS. Regarding the energy E, we showed back in chapter 2 that

(εv)T=T(pT)Vp=av2 ,

which entails

ε(T,v)=12fRTav ,

where ε=E/ν is the molar internal energy. The first term is the molar energy of an ideal gas, where f is the number of molecular freedoms, which is the appropriate low density limit. The molar specific heat is then cV=(εT)v=f2R, which means that the molar entropy is

s(T,v)=TdT cVT=f2Rln(T/Tc)+s1(v) .

We then write f=εTs, and we fix the function s1(v) by demanding that p=(fv)T . This yields s1(v)=Rln(vb)+s0, where s0 is a constant. Thus2,

f(T,v)=f2RT(1ln(T/Tc))avRTln(vb)Ts0 .

Table 7.1.1: van der Waals parameters for some common gases. (Source: Wikipedia)
gas a (L2barmol2) b (Lmol) pc (bar) Tc (K) vc ( L/mol)
Acetone 14.09 0.0994 52.82 505.1 0.2982
Argon 1.363 0.03219 48.72 150.9 0.0966
Carbon dioxide 3.640 0.04267 7404 304.0 0.1280
Ethanol 12.18 0.08407 63.83 516.3 0.2522
Freon 10.78 0.0998 40.09 384.9 0.2994
Helium 0.03457 0.0237 2.279 5.198 0.0711
Hydrogen 0.2476 0.02661 12.95 33.16 0.0798
Mercury 8.200 0.01696 1055 1723 0.0509
Methane 2.283 0.04278 46.20 190.2 0.1283
Nitrogen 1.408 0.03913 34.06 128.2 0.1174
Oxygen 1.378 0.03183 50.37 154.3 0.0955
Water 5.536 0.03049 220.6 647.0 0.0915

We know that under equilibrium conditions, f is driven to a minimum by spontaneous processes. Now suppose that 2fv2|T<0 over some range of v at a given temperature T. This would mean that one mole of the system at volume v and temperature T could lower its energy by rearranging into two half-moles, with respective molar volumes v±δv, each at temperature T. The total volume and temperature thus remain fixed, but the free energy changes by an amount Δf=122fv2|T(δv)2<0. This means that the system is unstable – it can lower its energy by dividing up into two subsystems each with different densities ( molar volumes). Note that the onset of stability occurs when

2fv2|T=pv|T=1vκp=0 ,

which is to say when κp=. As we saw, this occurs at p=p(v), given in Equation [pstar].

However, this condition, 2fv2|T<0, is in fact too strong. That is, the system can be unstable even at molar volumes where 2fv2|T>0. The reason is shown graphically in Figure 7.1.2. At the fixed temperature T, for any molar volume v between vliquidv1 and vgasv2, the system can lower its free energy by phase separating into regions of different molar volumes. In general we can write

v=(1x)v1+xv2 ,

so v=v1 when x=0 and v=v2 when x=1. The free energy upon phase separation is simply

f=(1x)f1+xf2 ,

where fj=f(vj,T). This function is given by the straight black line connecting the points at volumes v1 and v2 in Figure 7.1.2.

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Figure 7.1.2 Molar free energy f(T,v) of the van der Waals system T=0.85Tc, with dot-dashed black line showing Maxwell construction connecting molar volumes v1,2 on opposite sides of the coexistence curve.

The two equations which give us v1 and v2 are

fv|v1,T= fv|v2,T=f(T,v2)f(T,v1)(v2v1).

Equivalently, in terms of the pressure, p=fv|T , these equations are equivalent to

p(T,v1)=p(T,v2)=1v2v1v2v1dvp(T,v).

This procedure is known as the Maxwell construction, and is depicted graphically in Figure 7.1.3. When the Maxwell construction is enforced, the isotherms resemble the curves in Figure 7.1.1. In this figure, all points within the purple shaded region have 2fv2<0, hence this region is unstable to infinitesimal fluctuations. The boundary of this region is called the spinodal, and the spontaneous phase separation into two phases is a process known as spinodal decomposition. The dot-dashed orange curve, called the coexistence curve, marks the instability boundary for nucleation. In a nucleation process, an energy barrier must be overcome in order to achieve the lower free energy state. There is no energy barrier for spinodal decomposition – it is a spontaneous process.

Analytic form of the coexistence curve near the critical point

We write vL=vc+wL and vG=vc+wG. One of our equations is p(vc+wL,T)=p(vc+wG,T). Taylor expanding in powers of wL and wG , we have

0=pv(vc,T)(wGwL)+12pvv(vc,T)(w2Gw2L)+16pvvv(vc,T)(w3Gw3L)+ ,

where

pvpv,pvv2pv2,pvvv3pv3,pvT2pvT,etc.

The second equation we write as

wGwLdwp(vc+w,T)=12(wGwL)(p(vc+wL,T)+p(vc+wG,T)) .

Expanding in powers of wL and wG, this becomes

p(vc,T)(wGwL)+12pv(vc,T)(w2Gw2L)+16pvv(vc,T)(w3Gw3L)+124pvvv(vc,T)(w4Gw4L)+1120pvvvv(vc,T)(w5Gw5L)+=12(wGwL){2p(vc,T)+pv(vc,T)(wG+wL)+12pvv(vc,T)(w2G+w2L)+16pvvv(vc,T)(w3G+w3L)+124pvvvv(vc,T)(w4G+w4L)+}

Subtracting the LHS from the RHS, we find that we can then divide by 16(w2Gw2L), resulting in

0=pvv(vc,T)+12pvvv(vc,T)(wG+wL)+120pvvvv(vc,T)(3w2G+4wGwL+3w2L)+O(w3G,L) .

We now define w±wG±wL. In terms of these variables, Equations ??? and ??? become

0=pv(vc,T)+12pvv(vc,T)w++18pvvv(vc,T)(w2++13w2)+O(w3±)i0=pvv(vc,T)+12pvvv(vc,T)w++18pvvvv(vc,T)(w2++15w2)+O(w3±) .

clipboard_ee217351fa7cbba458a1f900b1b6b95c0.png

Figure 7.1.3: Maxwell construction in the (v,p) plane. The system is absolutely unstable between volumes vd and ve. For v[va,vd] of v[ve,vc], the solution is unstable with respect to phase separation. Source: Wikipedia.

We now evaluate w± to order T. Note that pv(vc,Tc)=pvv(vc,Tc)=0, since the critical point is an inflection point in the (v,p) plane. Thus, we have pv(vc,T)=pvTΘ+O(Θ2), where T=Tc+Θ and pvT=pvT(vc,Tc). We can then see that w is of leading order Θ, while w+ is of leading order Θ. This allows us to write

0=pvTΘ+124pvvvw2+O(Θ2)i0=pvvTΘ+12pvvvw++140pvvvvw2+O(Θ2) .

Thus,

w=(24pvTpvvv)1/2Θ+iw+=(6pvTpvvvv10pvvvpvvT5p2vvv)Θ+ .

We then have

wL=(6pvTpvvv)1/2Θ+(3pvTpvvvv5pvvvpvvT5p2vvv)Θ+O(Θ3/2)iwG=(6pvTpvvv)1/2Θ+(3pvTpvvvv5pvvvpvvT5p2vvv)Θ+O(Θ3/2) .

Suppose we follow along an isotherm starting from the high molar volume (gas) phase. If T>Tc, the volume v decreases continuously as the pressure p increases. If T<Tc, then at the instant the isotherm first intersects the orange boundary curve in Figure 7.1.4, there is a discontinuous change in the molar volume from high (gas) to low (liquid). This discontinuous change is the hallmark of a first order phase transition. Note that the volume discontinuity, Δv=w(TcT)1/2. This is an example of a critical behavior in which the order parameter ϕ, which in this case may be taken to be the difference ϕ=vGvL, behaves as a power law in |TTc|, where Tc is the critical temperature. In this case, we have ϕ(T)(TcT)β+, where β=12 is the exponent, and where (TcT)+ is defined to be TcT if T<Tc and 0 otherwise. The isothermal compressibility is κT=v/pv(v,T). This is finite along the coexistence curve – it diverges only along the spinodal. It therefore diverges at the critical point, which lies at the intersection of the spinodal and the coexistence curve.

clipboard_e28e0eb4caad64a467019fe3210c3f05b.png
Figure 7.1.4: Pressure-volume isotherms for the van der Waals system, as in Figure 7.1.1, but corrected to account for the Maxwell construction. The boundary of the purple shaded region is the spinodal line ˉp(ˉv). The boundary of the orange shaded region is the stability boundary with respect to phase separation.

It is convenient to express the equation of state and the coexistence curve in terms of dimensionless variables. Write

ˉp=ppc,ˉv=vvc,ˉT=TTc.

The van der Waals equation of state then becomes

ˉp=8ˉT3ˉv13ˉv2 .

Further expressing these dimensionless quantities in terms of distance from the critical point, we write

ˉp=1+π,ˉv=1+ϵ,ˉT=1+t .

Thus,

π(ϵ,t)=8(1+t)2+3ϵ3(1+ϵ)21 .

Note that the LHS and the RHS of this equation vanish identically for (π,ϵ,t)=(0,0,0). We can then write

ϵL,G=(6πϵtπϵϵϵ)1/2(t)1/2+(3πϵtπϵϵϵϵ5πϵϵϵπϵϵt5π2ϵϵϵ)t+O((t)3/2) .

History of the van der Waals equation

The van der Waals equation of state first appears in van der Waals’ 1873 PhD thesis3, “Over de Continuïteit van den Gas - en Vloeistoftoestand” (“On the continuity of the gas and liquid state”). In his Nobel lecture4, van der Waals writes of how he was inspired by Rudolf Clausius’ 1857 treatise on the nature of heat, where it is posited that a gas in fact consists of microscopic particles whizzing around at high velocities. van der Waals reasoned that liquids, which result when gases are compressed, also consist of ’small moving particles’: "Thus I conceived the idea that there is no essential difference between the gaseous and the liquid state of matter…"

clipboard_e82116e626b80f6598b03e88e63772132.png

Figure [Gugg1945] ‘Universality’ of the liquid-gas transition for eight different atomic and molecular fluids, from E. A. Guggenheim, J. Chem. Phys. 13, 253 (1945). Dimensionless temperature T/Tc versus dimensionless density ρ/ρc=vc/v is shown. The van der Waals / mean field theory gives Δv=vgasvliquid(t)1/2, while experiments show a result closer to Δv(t)1/3. Here tˉT1=(TTc)/Tc is the dimensionless temperature deviation with respect to the critical point. Image used without permission.

Clausius’ treatise showed how his kinetic theory of heat was consistent with Boyle’s law for gases ( pV=constant at fixed temperature). van der Waals pondered why this might fail for the non-dilute liquid phase, and he reasoned that there were two principal differences: inter-particle attraction and excluded volume. These considerations prompted him to posit his famous equation,

p=RTvbav2.

The first term on the RHS accounts for excluded volume effects, and the second for mutual attractions.

In the limiting case of p, the molar volume approaches v=b. On physical grounds, one might expect b=v0/ζ, where v0=NAω0 is NA times the volume ω0 of a single molecule, and the packing fraction is ζ=Nω0/V=v0/v, which is the ratio of the total molecular volume to the total system volume. In three dimensions, the maximum possible packing fraction is for fcc and hcp lattices, each of which have coordination number 12, with ζmax=π32=0.74078. Dense random packing results in ζdrp=0.634. Expanding the vdW equation of state in inverse powers of v yields

p=RTv+(baRT)RTv2+O(v3) ,

and we read of the second virial coefficient B2=(baRT)/NA. For hard spheres, a=0, and the result B2=4ω0 from the Mayer cluster expansion corresponds to bMayer=4v0 , which is larger than the result from even the loosest regular sphere packing, that for a cubic lattice, with ζcub=π6.

Another of van der Waals’ great achievements was his articulation of the law of corresponding states. Recall that the van der Waals equation of state, when written in terms of dimensionless quantities ˉp=p/pc , ˉv=v/vc , and ˉT=T/Tc, takes the form of Equation ???. Thus, while the a and b parameters are specific to each fluid – see Table 7.1.1 – when written in terms of these scaled dimensionless variables, the equation of state and all its consequent properties ( the liquid-gas phase transition) are universal.

The van der Waals equation is best viewed as semi-phenomenological. Interaction and excluded volume effects surely are present, but the van der Waals equation itself only captures them in a very approximate way. It is applicable to gases, where it successfully predicts features that are not present in ideal systems ( throttling). It is of only qualitative and pedagogical use in the study of fluids, the essential physics of which lies in the behavior of quantities like the pair distribution function g(r). As we saw in chapter 6, any adequate first principles derivation of g(r) - a function which can be measured in scattering experiments - involves rather complicated approximation schemes to close the BBGKY hierarchy. Else one must resort to numerical simulations such as the Monte Carlo method. Nevertheless, the lessons learned from the van der Waals system are invaluable and they provide us with a first glimpse of what is going on in the vicinity of a phase transition, and how nonanalytic behavior, such as vGvL(TcT)β with noninteger exponent β may result due to singularities in the free energy at the critical point.


This page titled 7.1: The van der Waals system is shared under a CC BY-NC-SA license and was authored, remixed, and/or curated by Daniel Arovas.

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