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Physics LibreTexts

19.13: Hybrid Orbitals - sp³

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Upward view of tall, slender, golden-brown reeds against a clear blue sky. Figure 19.13.1: (Public Domain; Priit Kallas (Wikimedia: Pk2000) via Wikipedia)

Do you recognize this plant?

If we were walking on the beach, the plants shown above would look very different. They would be short and sticking out of the sand. When we see them this way, we may not immediately recognize them as beach plants. Often, we need to look at the world around us in different ways to understand things better.

Hybrid Orbitals - sp3

The bonding scheme described by valence bond theory must account for molecular geometries as predicted by VSEPR theory. To do that, we must introduce the concept of hybrid orbitals.

sp3 Hybridization

Unfortunately, overlap of existing atomic orbitals (s, p, etc.) is not sufficient to explain some of the bonding and molecular geometries that are observed. Consider the element carbon and the methane (CH4) molecule. A carbon atom has the electron configuration of 1s22s22p2, meaning that it has two unpaired electrons in its 2p orbitals, as shown in the figure below.

Diagram showing electron orbital configuration. The 2s orbital has two opposing arrows in one box, while the 2p orbital has two upward arrows each in a separate box, and one box is empty. Figure 19.13.2: Orbital configuration for carbon atom. (CC BY-NC 3.0; Joy Sheng via CK-12 Foundation)

According to the description of valence bond theory so far, carbon would be expected to form only two bonds, corresponding to its two unpaired electrons. However, methane is a common and stable molecule, with four equivalent CH bonds. To account for this, one of the 2s electrons is promoted to the empty 2p orbital (see figure below).

An illustration showing electron configuration. A box labeled 2s with one upward arrow and a group of three boxes labeled 2p, each containing an upward arrow. Figure 19.13.3: Promotion of carbon s electron to empty p orbital. (CC BY-NC 3.0; Joy Sheng via CK-12 Foundation)

Now, four bonds are possible. The promotion of the electron "costs" a small amount of energy, but recall that the process of bond formation is accompanied by a decrease in energy. The two extra bonds that can now be formed results in a lower overall energy, and thus greater stability to the CH4 molecule. Carbon normally forms four bonds in most of its compounds.

The number of bonds is now correct, but the geometry is wrong. The three p orbitals, (px, py, and pz), are oriented at 90o relative to one another. However, as seen in VSEPR theory, the observed HCH bond angle in the tetrahedral CH4 molecule is actually 109.5o. Therefore, the methane molecule cannot be adequately represented by simple overlap of the 2s and 2p orbitals of carbon with the 1s orbitals of each hydrogen atom.

To explain the bonding in methane, it is necessary to introduce the concept of hybridization and hybrid atomic orbitals. Hybridization is the mixing of the atomic orbitals in an atom to produce a set of hybrid orbitals. When hybridization occurs, it must do so as a result of the mixing of nonequivalent orbitals. In other words, s and p orbitals can hybridize, but p orbitals cannot hybridize with other p orbitals. Hybrid orbitals are the atomic orbitals obtained when two or more nonequivalent orbitals from the same atom combine in preparation for bond formation. In the current case of carbon, the single 2s orbital hybridizes with the three 2p orbitals to form a set of four hybrid orbitals, called sp3 hybrids (see figure below).

Diagram of electron configuration showing four arrows pointing up in four connected boxes labeled 2sp³. Figure 19.13.4: Carbon sp3 hybrid orbitals. (CC BY-NC 3.0; Joy Sheng via CK-12 Foundation)

The sp3 hybrids are all equivalent to one another. Spatially, the hybrid orbitals point towards the four corners of a tetrahedron (see figure below).

Diagram showing atomic orbitals: spherically symmetric s-orbital, p-orbitals along x, y, z axes, hybridization forming sp³ orbitals, with a final depiction of a symmetrical red lobe structure. Figure 19.13.5: The process of sp3 hybridization is the mixing of an s orbital with a set of three p orbitals to form a set of four sp3 hybrid orbitals. Each large lobe of the hybrid orbitals points to one corner of a tetrahedron. The four lobes of each of the sp3 hybrid orbitals then overlap with the normal unhybridized 1s orbitals of each hydrogen atom to form the tetrahedral methane molecule. (CC BY-NC 3.0; Jodi So via CK-12 Foundation)

Summary

  • Electrons hybridize in order to form covalent bonds.
  • Nonequivalent orbitals mix to form hybrid orbitals.

Review

  • Why is carbon expected to form only two covalent bonds?
  • How many covalent bonds does carbon actually form?
  • What needs to happen to allow carbon to form four bonds?

This page titled 19.13: Hybrid Orbitals - sp³ is shared under a CK-12 license and was authored, remixed, and/or curated by CK-12 Foundation via source content that was edited to the style and standards of the LibreTexts platform.

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