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1.9: Centripetal Acceleration

  • Page ID
    46796
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    Learning Objectives

    • Explain what centripetal acceleration is.
    • Use the formula for centripetal acceleration in simple situations.

    We defined acceleration as a change in velocity, either in its magnitude or in its direction, or both. When an object moves along a circular path, the direction of its velocity changes constantly, so there is always an associated acceleration, even if the speed of the object is constant. You experience this acceleration yourself when you turn a corner in your car. What you notice is a sideways acceleration because you and the car are changing direction. The sharper the curve and the greater your speed, the more noticeable this acceleration will become. In this section we briefly examine the direction and magnitude of that acceleration.

    Figure \(\PageIndex{1}\) shows an object moving in a circular path at constant speed, called uniform circular motion. The direction of the instantaneous velocity is shown at two points along the path. Acceleration is in the direction of the change in velocity, which points directly toward the center of rotation (the center of the circular path). This pointing is shown with the vector diagram in the figure. We call the acceleration of an object moving in uniform circular motion (resulting from a net external force) the centripetal acceleration(\(a_{\mathrm{c}}\)); centripetal means “toward the center” or “center seeking.”

    fig-ch01_patchfile_01.jpg
    Figure \(\PageIndex{1}\): The directions of the velocity of an object at two different points are shown, and the change in velocity \(\Delta \mathbf{v}\) is seen to point directly toward the center of curvature. (See small inset.) Because \(\mathbf{a}_{\mathbf{c}}=\Delta \mathbf{v} / \Delta t\), the acceleration is also toward the center; \(a_{\mathrm{c}}\) is called centripetal acceleration. (For small time differences, \(\Delta \theta \) is very small, and the arc length \(\Delta s\) is approximately equal to the chord length \(\Delta r\).)

    The direction of centripetal acceleration is toward the center of curvature, but what is its magnitude? If we use the geometry shown in Figure \(\PageIndex{1}\) along with some kinematics equations, we can obtain (detailed derivation skipped)

    \[a_{\mathrm{c}}=\frac{v^{2}}{r}, \label{Equation1} \]

    which is the acceleration of an object in a circle of radius \(r\) at a speed \(v\). Verify for yourself that \(a_{\mathrm{c}}\) has unit of \(\mathrm{m} / \mathrm{s}^{2}\), as expected for acceleration.

    We see in Equation \(\eqref{Equation1}\) that centripetal acceleration is greater at high speeds and in sharp curves (smaller radius), as you have noticed when driving a car. But it is a bit surprising that \(a_{\mathrm{c}}\) is proportional to speed squared, implying, for example, that it is four times as hard to take a curve at 100 km/h than at 50 km/h. A sharp corner has a small radius, so that \(a_{\mathrm{c}}\) is greater for tighter turns, as you have probably noticed.

    Section Summary

    • Centripetal acceleration \(a_{\mathrm{c}}\) is the acceleration experienced while in uniform circular motion. It always points toward the center of rotation. It is perpendicular to the linear velocity \(v\) and has the magnitude

      \[a_{\mathrm{c}}=\frac{v^{2}}{r}. \nonumber\]

    • The unit of centripetal acceleration is \(\mathrm{m} / \mathrm{s}^{2}\).

    This page titled 1.9: Centripetal Acceleration is shared under a CC BY 4.0 license and was authored, remixed, and/or curated by OpenStax.

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