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2.2G: Potential on the Axis of a Charged Disc

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    5841

    • The field on the axis of a charged disc is given in section 1.6.5. The reader is invited to show that the potential on the axis of the disc is

    \[V=\frac{2Q}{4\pi\epsilon_0 a^2}[(a^2+x^2)^{1/2}-x].\tag{2.2.9}\]