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5.6: Capacitors in Series

Last updated

Mar 5, 2022
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- 5.5: Capacitors in Parallel
- 5.7: Delta-Star Transform

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V.6.png

$\text{FIGURE V.6}$

The charge is the same on each, and the potential difference across the system is the sum of the potential differences across the individual capacitances. Hence

$\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}+\dfrac{1}{C_3}.\label{5.6.1}$

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