2.4: Higher Orders
( \newcommand{\kernel}{\mathrm{null}\,}\)
It may turn out that the matrix element V00 is zero, often due to symmetry. In this case we must consider what happens at second order. Going back to equation 1, and using our expression for mixing and assumption c00≈1
ΔE0=0+∑i=1,∞⟨ni|ˆV|n0⟩V0i(E0−Ei)=∑i=1,∞|Vi0|2(E0−Ei)