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14.6: RLC Series Circuits

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  • When the switch is closed in the RLC circuit of Figure(a), the capacitor begins to discharge and electromagnetic energy is dissipated by the resistor at a rate \(i^2 R\). With U given by [link], we have

    \[\frac{dU}{dt} = \frac{q}{C} \frac{dq}{dt} + Li \frac{di}{dt} = -i^2 R\]

    where i and q are time-dependent functions. This reduces to

    \[L\frac{d^2q}{dt^2} + R\frac{dq}{dt} + \frac{1}{C}q = 0.\]

    Figure a is a circuit with a capacitor, an inductor and a resistor in series with each other. They are also in series with a switch, which is open. Figure b shows the graph of charge versus time. The charge is at maximum value, q0, at t=0. The curve is similar to a sine wave that reduces in amplitude till it becomes zero

    Figure \(\PageIndex{1}\): (a) An RLC circuit. Electromagnetic oscillations begin when the switch is closed. The capacitor is fully charged initially. (b) Damped oscillations of the capacitor charge are shown in this curve of charge versus time, or q versus t. The capacitor contains a charge \(q_0\) before the switch is closed.

    This equation is analogous to

    \[m\frac{d^2x}{dt^2} + b\frac{dx}{dt} + kx = 0,\]

    which is the equation of motion for a damped mass-spring system (you first encountered this equation in Oscillations). As we saw in that chapter, it can be shown that the solution to this differential equation takes three forms, depending on whether the angular frequency of the undamped spring is greater than, equal to, or less than b/2m. Therefore, the result can be underdamped \((\sqrt{k/m} > b/2m)\), critically damped \((\sqrt{k/m} = b/2m)\), or overdamped \((\sqrt{k/m} < b/2m)\). By analogy, the solution q(t) to the RLC differential equation has the same feature. Here we look only at the case of under-damping. By replacing m by L, b by R, k by 1/C, and x by q in Equation, and assuming \(\sqrt{1/LC} > R/2L\), we obtain


    \[q(t) = q_0 e^{-Rt/2L} cos (\omega't + \phi)\]

    where the angular frequency of the oscillations is given by


    \[\omega' = \sqrt{\frac{1}{LC} - \left(\frac{R}{2L}\right)^2}\]

    This underdamped solution is shown in Figure(b). Notice that the amplitude of the oscillations decreases as energy is dissipated in the resistor. Equation can be confirmed experimentally by measuring the voltage across the capacitor as a function of time. This voltage, multiplied by the capacitance of the capacitor, then gives q(t).


    Try an interactive circuit construction kit that allows you to graph current and voltage as a function of time. You can add inductors and capacitors to work with any combination of R, L, and C circuits with both dc and ac sources.


    Try out a circuit-based java applet website that has many problems with both dc and ac sources that will help you practice circuit problems.


    Check Your Understanding

    In an RLC circuit, \(L = 5.0 \, mH\), \(C = 6.0 \, \mu F\), and \(R = 200 \, \Omega\). (a) Is the circuit underdamped, critically damped, or overdamped? (b) If the circuit starts oscillating with a charge of \(3.0 \times 10^{-3}C\) on the capacitor, how much energy has been dissipated in the resistor by the time the oscillations cease?

    [Hide Solution]

    a. overdamped; b. 0.75 J


    Paul Peter Urone (Professor Emeritus at California State University, Sacramento) and Roger Hinrichs (State University of New York, College at Oswego) with Contributing Authors: Kim Dirks (University of Auckland) and Manjula Sharma (University of Sydney). This work is licensed by OpenStax University Physics under a Creative Commons Attribution License (by 4.0).