22.6: Frequency Multiples
( \newcommand{\kernel}{\mathrm{null}\,}\)
The above analysis is for frequencies not very far from \omega_{0}. But nonlinear terms can cause resonance to occur at frequencies which are rational multiples of \omega_{0}. Landau shows that a small \dfrac{1}{3} \alpha x^{3} in the potential (so an additional force \alpha x^{2} in the equation of motion) can generate a resonance near \gamma=\dfrac{1}{2} \omega_{0}. We’ve only considered a quartic addition to the potential, \dfrac{1}{4} \beta x^{4}, \text { a force } \beta x^{3}, we can show that gives a resonance near \gamma=\dfrac{1}{3} \omega_{0}, and presumably this is the small bump near the beginning of the curves above for large driving strength.
\text { We have } \ddot{x}+2 \lambda \dot{x}+\omega_{0}^{2} x=(f / m) \cos \gamma t-\beta x^{3}
\text { We'll write } x=x^{(0)}+x^{(1)}+\ldots
\text { Let's define } x^{(0)} \text { by }
\ddot{x}^{(0)}+2 \lambda \dot{x}^{(0)}+\omega_{0}^{2} x^{(0)}=(f / m) \cos \gamma t
\text { So } x^{(0)}=b \cos (\gamma t+\delta) . \text { Then }
\begin{aligned} \ddot{x}^{(1)}+2 \lambda \dot{x}^{(1)}+\omega_{0}^{2} x^{(1)} &=-\beta\left(x^{(0)}\right)^{3} \\ &=-\beta b^{3} \cos ^{3}(\gamma t+\delta) \\ &=-\beta b^{3}\left[\dfrac{3}{4} \cos (\gamma t+\delta)+\dfrac{1}{4} \cos (3 \gamma t+\delta)\right] \end{aligned}
Then, for \gamma=\dfrac{1}{3} \omega_{0}, the second term, -\beta b^{3} \dfrac{1}{4} \cos (3 \gamma t+\delta)=-\beta b^{3} \dfrac{1}{4} \cos \left(\omega_{0} t+\delta\right), will have a resonant response, although it is proportional to the (small) amplitude cubed. Similar arguments work for other fractional frequencies.