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3.5: Two-element circuits and RLC resonators

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    Two-element circuits and uncoupled RLC resonators

    RLC resonators typically consist of a resistor R, inductor L, and capacitor C connected in series or parallel, as illustrated in Figure 3.5.1. RLC resonators are of interest because they behave much like other electromagnetic systems that store both electric and magnetic energy, which slowly dissipates due to resistive losses. First we shall find and solve the differential equations that characterize RLC resonators and their simpler sub-systems: RC, RL, and LC circuits. This will lead to definitions of resonant frequency ωo and Q, which will then be related in Section 3.5.2 to the frequency response of RLC resonators that are coupled to circuits.

    Figure 3.5.1.PNG
    Figure \(\PageIndex{1}\): Series and parallel RLC resonators.

    The differential equations that govern the voltages across R’s, L’s, and C’s are, respectively:

    \[ \mathrm{v}_{\mathrm{R}}=\mathrm{iR}\]

    \[\mathrm{v}_{\mathrm{L}}=\mathrm{L} \ \mathrm{di} / \mathrm{dt}\]

    \[\mathrm{v}_{\mathrm{C}}=(1 / \mathrm{C}) \int \mathrm{i} \ \mathrm{d} \mathrm{t}\]

    Kirchoff’s voltage law applied to the series RLC circuit of Figure 3.5.1(a) says that the sum of the voltages (3.5.1), (3.5.2), and (3.5.3) is zero:

    \[\mathrm{d}^{2} \mathrm{i} / \mathrm{dt}^{2}+(\mathrm{R} / \mathrm{L}) \mathrm{di} / \mathrm{dt}+(1 / \mathrm{LC}) \mathrm{i}=0 \]

    where we have divided by L and differentiated to simplify the equation. Before solving it, it is useful to solve simpler versions for RC, RL, and LC circuits, where we ignore one of the three elements.

    In the RC limit where L = 0 we add (3.5.1) and (3.5.3) to yield the differential equation:

    \[ \mathrm{di} / \mathrm{dt}+(1 / \mathrm{RC}) \mathrm{i}=0\]

    This says that i(t) can be any function with the property that the first derivative is the same as the original signal, times a constant. This property is restricted to exponentials and their sums, such as sines and cosines. Let's represent i(t) by Ioest, where:

    \[\mathrm{i}(\mathrm{t})=\mathrm{R}_{\mathrm{e}}\left\{\mathrm{I}_{\mathrm{o}} \mathrm{e}^{\mathrm{st}}\right\}\]

    where the complex frequency s is:

    \[\mathrm{s} \equiv \alpha+\mathrm{j} \omega\]

    We can substitute (3.5.6) into (3.5.5) to yield:

    \[\operatorname{Re}\left\{[\mathrm{s}+(1 / \mathrm{RC})] \mathrm{I}_{0} \mathrm{e}^{\mathrm{st}}\right\}=0\]

    Since est is not always zero, to satisfy (3.5.8) it follows that s = - 1/RC and:

    \[\mathrm{i}(\mathrm{t})=\mathrm{I}_{\mathrm{o}} \mathrm{e}^{-(1 / \mathrm{RC}) \mathrm{t}}=\mathrm{I}_{\mathrm{o}} \mathrm{e}^{-\mathrm{t} / \tau} \qquad\qquad\qquad \text{(RC current response)}\]

    where \(\tau\) equals RC seconds and is the RC time constant. Io is chosen to satisfy initial conditions, which were not given here.

    A simple example illustrates how initial conditions can be incorporated in the solution. We simply need as many equations for t = 0 as there are unknown variables. In the present case we need one equation to determine Io. Suppose the RC circuit [of Figure 3.5.1(a) with L = 0] was at rest at t = 0, but the capacitor was charged to Vo volts. Then we know that the initial current Io at t = 0 must be Vo/R.

    In the RL limit where C = ∞ we add (3.5.1) and (3.5.2) to yield di/dt + (R/L)i = 0, which has the same form of solution (3.5.6), so that s = -R/L and:

    \[\mathrm{i}(\mathrm{t})=\mathrm{I}_{\mathrm{o}} \mathrm{e}^{-(\mathrm{R} / \mathrm{L}) \mathrm{t}}=\mathrm{I}_{\mathrm{o}} \mathrm{e}^{-\mathrm{t} / \tau} \qquad\qquad\qquad \text{(RL current response) }\]

    where the RL time constant \(\tau\) is L/R seconds.

    In the LC limit where R = 0 we add (3.5.2) and (3.5.3) to yield:

    \[\mathrm{d}^{2} \mathrm{i} / \mathrm{dt}^{2}+(1 / \mathrm{LC}) \mathrm{i}=0\]

    Its solution also has the form (3.5.6). Because i(t) is real and ejωt is complex, it is easier to assume sinusoidal solutions, where the phase φ and magnitude Io would be determined by initial conditions. This form of the solution would be:

    \[\mathrm{i}(\mathrm{t})=\mathrm{I}_{\mathrm{o}} \cos \left(\omega_{\mathrm{o}} \mathrm{t}+\phi\right) \qquad\qquad\qquad \text{(LC current response)}\]

    where ωo = 2\(\pi\)fo is found by substituting (3.5.12) into (3.5.11) to yield [ωo2 – (LC)-1]i(t) = 0, so:

    \[\omega_{\mathrm{o}}=\frac{1}{\sqrt{\mathrm{L} C}} \ \left[\text { radians } \mathrm{s}^{-1}\right] \qquad \qquad \qquad \text{ (LC resonant frequency) }\]

    We could alternatively express this solution (3.5.12) as the sum of two exponentials using the identity \(\cos \omega t \equiv\left(e^{j \omega t}+e^{-j \omega t}\right) / 2\).

    RLC circuits exhibit both oscillatory resonance and exponential decay. If we substitute the generic solution \(\underline{I}_{0} \mathrm{e}^{\mathrm{st}}\) (3.5.6) into the RLC differential equation (3.5.4) for the series RLC resonator of Figure 3.5.1(a) we obtain:

    \[\left(s^{2}+s R / L+1 / L C\right) \underline{I}_{0} e^{s t}=\left(s-s_{1}\right)\left(s-s_{2}\right) \underline{I}_{0} e^{s t}=0\]

    The RLC resonant frequencies s1 and s2 are solutions to (3.5.14) and can be found by solving this quadratic equation9 to yield:

    \[\mathrm{s}_{\mathrm{i}}=-\mathrm{R} / 2 \mathrm{L} \pm \mathrm{j}\left[(1 / \mathrm{LC})-(\mathrm{R} / 2 \mathrm{L})^{2}\right]^{0.5} \qquad \qquad \qquad \text{(series RLC resonant frequencies) }\]

    When R = 0 this reduces to the LC resonant frequency solution (3.5.13).

    9 A quadratic equation in x has the form ax2 + bx + c = 0 and the solution x = (-b ± [b2 - 4ac]0.5)/2a.

    The generic solution \( \mathrm{i}(\mathrm{t})=\mathrm{\underline{I}}_{\mathrm{o}}^{\prime} \mathrm{e}^{\mathrm{st}}\) is complex, where \(\underline{I}_{0}^{\prime} \equiv \mathrm{I}_{0} \mathrm{e}^{\mathrm{j} \phi} \):

    \[\mathrm{i}(\mathrm{t})=\mathrm{R}_{\mathrm{e}}\left\{\mathrm{\underline{I}}_{\mathrm{o}}^{\prime} \mathrm{e}^{\mathrm{s}_{1} \mathrm{t}}\right\}=\mathrm{R}_{\mathrm{e}}\left\{\mathrm{I}_{\mathrm{o}} \mathrm{e}^{\mathrm{j} \phi} \mathrm{e}^{-(\mathrm{R} / 2 \mathrm{L}) \mathrm{t}} \mathrm{t}^{\mathrm{j} \omega \mathrm{t}}\right\}=\mathrm{I}_{\mathrm{o}} \mathrm{e}^{-(\mathrm{R} / 2 \mathrm{L}) \mathrm{t}} \cos (\omega \mathrm{t}+\phi)\]

    where \( \omega=\left[(\mathrm{LC})^{-1}+(\mathrm{R} / 2 \mathrm{L})^{2}\right]^{0.5} \cong(\mathrm{LC})^{-0.5}\). Io and φ can be found from the initial conditions, which are the initial current through L and the initial voltage across C, corresponding to the initial energy storage terms. If we choose the time origin so that the phase φ = 0, the instantaneous magnetic energy stored in the inductor (3.2.23) is:

    \[\mathrm{w}_{\mathrm{m}}(\mathrm{t})=\mathrm{Li}^{2} / 2=\left(\mathrm{LI}_{\mathrm{o}}^{2} / 2\right) \mathrm{e}^{-\mathrm{R} t / \mathrm{L}} \cos ^{2} \omega \mathrm{t}=\left(\mathrm{LI}_{\mathrm{o}}^{2} / 4\right) \mathrm{e}^{-\mathrm{R} t / \mathrm{L}}(1+\cos 2 \omega \mathrm{t})\]

    Because wm = 0 twice per cycle and energy is conserved, the peak electric energy we(t) stored in the capacitor must be intermediate between the peak magnetic energies stored in the inductor (eRt/LLIo2 /2) during the preceding and following cycles. Also, since dvC/dt = i/C, the cosine variations of i(t) produce a sinusoidal variation in the voltage vC(t) across the capacitor. Together these two facts yield: \( \mathrm{w}_{\mathrm{e}}(\mathrm{t}) \cong\left(\mathrm{LI}_{\mathrm{o}}^{2} / 2\right) \mathrm{e}^{-\mathrm{R} t / \mathrm{L}} \sin ^{2} \omega \mathrm{t}\). If we define Vo as the maximum initial voltage corresponding to the maximum initial current Io, and recall the expression (3.1.16) for we(t), we find:

    \[ \mathrm{w}_{\mathrm{e}}(\mathrm{t})=\mathrm{Cv}^{2} / 2 \cong\left(\mathrm{CV}_{\mathrm{o}}^{2} / 2\right) \mathrm{e}^{-\mathrm{R} t / \mathrm{L}} \sin ^{2} \omega \mathrm{t}=\left(\mathrm{CV}_{\mathrm{o}}^{2} / 4\right) \mathrm{e}^{-\mathrm{R} t / \mathrm{L}}(1-\cos 2 \omega \mathrm{t})\]

    Comparison of (3.5.17) and (3.5.18) in combination with conservation of energy yields:

    \[ \mathrm{V}_{\mathrm{o}} \cong(\mathrm{L} / \mathrm{C})^{0.5} \mathrm{I}_{\mathrm{o}}\]

    Figure 3.5.2 illustrates how the current and energy storage decays exponentially with time while undergoing conversion between electric and magnetic energy storage at 2ω radians s-1; the time constant for current and voltage is \(\tau\) = 2L/R seconds, and that for energy is L/R.

    One useful way to characterize a resonance is by the dimensionless quantity Q, which is the number of radians required before the total energy wT decays to 1/e of its original value, as illustrated in Figure 3.5.2(b). That is:

    \[\mathrm{w}_{\mathrm{T}}=\mathrm{w}_{\mathrm{To}} \mathrm{e}^{-2 \alpha \mathrm{t}}=\mathrm{w}_{\mathrm{To}} \mathrm{e}^{-\omega \mathrm{t} / \mathrm{Q}} \ [\mathrm{J}]\]

    The decay rate \(\alpha\) for current and voltage is therefore simply related to Q:

    \[ \alpha=\omega / 2 \mathrm{Q}\]

    Figure 3.5.2.PNG
    Figure \(\PageIndex{2}\): Time variation of current and energy storage in RLC circuits.

    If we find the power dissipated Pd [W] by differentiating total energy wT with respect to time using (3.5.20), we can then derive a common alternative definition for Q:

    \[\mathrm{P}_{\mathrm{d}}=-\mathrm{d} \mathrm{w}_{\mathrm{T}} / \mathrm{dt}=(\omega / \mathrm{Q}) \mathrm{w}_{\mathrm{T}}\]

    \[\mathrm{Q}=\omega \mathrm{w}_{\mathrm{T}} / \mathrm{P}_{\mathrm{d}} \qquad\qquad\qquad \text{(one definition of Q) }\]

    For the series RLC resonator \(\alpha\) = R/2L and ω ≅ (LC)-0.5, so (3.5.21) yields:

    \[\mathrm{Q}=\omega / 2 \alpha=\omega \mathrm{L} / \mathrm{R} \cong(\mathrm{L} / \mathrm{C})^{0.5} / \mathrm{R} \qquad\qquad\qquad \text{(Q of series RLC resonator) }\]

    Figure 3.5.1(b) illustrates a parallel RLC resonator. KCL says that the sum of the currents into any node is zero, so:

    \[\mathrm{C} \ \mathrm{dv} / \mathrm{dt}+\mathrm{v} / \mathrm{R}+(1 / \mathrm{L}) \int \mathrm{v} \ \mathrm{dt}=0\]

    \[\mathrm{d}^{2} \mathrm{v} / \mathrm{dt}^{2}+(1 / \mathrm{RC}) \mathrm{dv} / \mathrm{dt}+(1 / \mathrm{LC}) \mathrm{v}=0\]

    If v = Voest, then:

    \[\left[s^{2}+(1 / R C) s+(L / C)\right]=0\]

    \[\mathrm{s}=-(1 / 2 \mathrm{RC}) \pm \mathrm{j}\left[(1 / \mathrm{LC})-(1 / 2 \mathrm{RC})^{2}\right]^{0.5} \qquad \qquad \qquad \text{(parallel RLC resonance) }\]

    Analogous to (3.5.16) we find:

    \[\mathrm{v}(\mathrm{t})=\mathrm{R}_{\mathrm{e}}\left\{\underline{\mathrm{V}}_{\mathrm{o}}^{\prime} \mathrm{e}^{\mathrm{s}_{1} \mathrm{t}}\right\}=\mathrm{V}_{\mathrm{o}} \mathrm{e}^{-(1 / 2 \mathrm{R} \mathrm{C}) \mathrm{t}} \cos (\omega \mathrm{t}+\phi) \]

    where \( \underline{V}_{0}^{\prime}=V_{0} e^{j \phi}\). It follows that for a parallel RLC resonator:

    \[\omega=\left[(\mathrm{LC})^{-1}-(2 \mathrm{RC})^{-2}\right]^{0.5} \cong(\mathrm{LC})^{-0.5}\]

    \[Q=\omega / 2 \alpha=\omega R C=R(C / L)^{0.5} \qquad \qquad \qquad \text{(Q of parallel RLC resonator) }\]

    Example \(\PageIndex{A}\)

    What values of L and C would give a parallel resonator at 1 MHz a Q of 100 if R = 106/2\(\pi\)?

    Solution

    LC = 1/ωo2 = 1/(2\(\pi\)106)2 , and Q = 100 = ωRC = 2\(\pi\)106(106/2\(\pi\))C so C = 10-10 [F] and L = 1/ωo2 c ≅ 2.5×10-4 [Hy].

    Coupled RLC resonators

    RLC resonators are usually coupled to an environment that can be represented by either its Thevenin or Norton equivalent circuit, as illustrated in Figure 3.5.3(a) and (b), respectively, for purely resistive circuits.

    Figure 3.5.3.PNG
    Figure \(\PageIndex{3}\): Series and parallel RLC resonators driven by Thevenin and Norton equivalent circuits.

    A Thevenin equivalent consists of a voltage source VTh in series with an impedance \(\underline{Z}_{\mathrm{Th}}=\mathrm{R}_{\mathrm{Th}}+\mathrm{jX}_{\mathrm{Th}}\), while a Norton equivalent circuit consists of a current source INo in parallel with an admittance \(\underline{Y}_{\mathrm{No}}=\mathrm{G}_{\mathrm{No}}+\mathrm{jU}_{\mathrm{No}}\). The Thevenin equivalent of a resistive Norton equivalent circuit has open-circuit voltage VTh = INo/GNo, and RTh = 1/GNo; that is, their opencircuit voltages, short-circuit currents, and impedances are the same. No single-frequency electrical experiment performed at the terminals can distinguish ideal linear circuits from their Thevenin or Norton equivalents.

    An important characteristic of a resonator is the frequency dependence of its power dissipation. If RTh = 0, the series RLC resonator of Figure 3.5.3(a) dissipates:

    \[\mathrm{P}_{\mathrm{d}}=\mathrm{R}|\mathrm{\underline{I}}|^{2} / 2[\mathrm{W}]\]

    \[P_{d}=\left[R\left|\underline{V}_{T h}\right|^{2} / 2\right] /\left|R+L s+C^{-1} s^{-1}\right|^{2}=\left[R\left|\underline{V}_{T h}\right|^{2} / 2\right]|s / L|^{2} /\left|\left(s-s_{1}\right)\left(s-s_{2}\right)\right|^{2}\]

    where s1 and s2 are given by (3.5.15):

    \[\mathrm{s}_{\mathrm{i}}=-\mathrm{R} / 2 \mathrm{L} \pm \mathrm{j}\left[(1 / \mathrm{LC})-(\mathrm{R} / 2 \mathrm{L})^{2}\right]^{0.5}=-\alpha \pm \mathrm{j} \omega_{\mathrm{o}}^{\prime} \qquad\qquad\qquad \text { (series RLC resonances) }\]

    The maximum value of Pd is achieved when ω ≅ ω′o :

    \[P_{\mathrm{d} \max }=\left|\underline{\mathrm{V}}_{\mathrm{Th}}\right|^{2} / 2 \mathrm{R}\]

    This simple expression is expected since the reactive impedances of L and C cancel at ωo, leaving only R.

    If \((1 / \mathrm{LC}) \gg(\mathrm{R} / 2 \mathrm{L})\) so that \(\omega_{\mathrm{o}} \cong \omega_{\mathrm{o}}^{\prime}\), then as ω - ωo increases from zero to \(\alpha\), |s − s1 | = | jωo − (jωo + \(\alpha\)) | increases from \(\alpha\) to \(\sqrt{2} \alpha\). This departure from resonance approximately doubles the denominator of (3.5.33) and halves Pd. As ω departs still further from ωo and resonance, Pd eventually approaches zero because the impedances of L and C approach infinity at infinite and zero frequency, respectively. The total frequency response Pd(f) of this series RLC resonator is suggested in Figure 3.5.4. The resonator bandwidth or half-power bandwidth Δω is said to be the difference between the two half-power frequencies, or Δω ≅ 2\(\alpha\) = R/L for this series circuit. Δω is simply related to ωo and Q for both series and parallel resonances, as follows from (3.5.21):

    \[\mathrm{Q}=\omega_{\mathrm{o}} / 2 \alpha=\omega_{\mathrm{o}} / \Delta \omega \qquad \qquad \qquad \text{(Q versus bandwidth) }\]

    Parallel RLC resonators behave similarly except that:

    \[ \mathrm{s}_{\mathrm{i}}=-\mathrm{G} / 2 \mathrm{L} \pm \mathrm{j}\left[(1 / \mathrm{LC})-(\mathrm{G} / 2 \mathrm{L})^{2}\right]^{0.5}=-\alpha \pm \mathrm{j} \omega_{\mathrm{o}}^{\prime} \qquad\qquad\qquad \text{(parallel RLC resonances) }\]

    where R, L, and C in (3.5.34) have been replaced by their duals G, C, and L, respectively.

    Figure 3.5.4.PNG
    Figure \(\PageIndex{4}\): RLC power dissipation near resonance.

    Resonators reduce to their resistors at resonance because the impedance of the LC portion approaches zero or infinity for series or parallel resonators, respectively. At resonance Pd is maximized when the source Rs and load R resistances match, as is easily shown by setting the derivative dPd/dR = 0 and solving for R. In this case we say the resonator is critically matched to its source, for all available power is then transferred to the load at resonance.

    This critically matched condition can also be related to the Q’s of a coupled resonator with zero Thevenin voltage applied from outside, where we define internal Q (or QI) as corresponding to power dissipated internally in the resonator, external Q (or QE) as corresponding to power dissipated externally in the source resistance, and loaded Q (or QL) as corresponding to the total power dissipated both internally (PDI) and externally (PDE). That is, following (3.5.23):

    \[\mathrm{Q}_{\mathrm{I}} \equiv \omega \mathrm{w}_{\mathrm{T}} / \mathrm{P}_{\mathrm{DI}} \qquad\qquad\qquad \text{(internal Q) }\]

    \[\mathrm{Q}_{\mathrm{E}} \equiv \omega \mathrm{w}_{\mathrm{T}} / \mathrm{P}_{\mathrm{DE}} \qquad\qquad\qquad \text{(external Q) }\]

    \[\mathrm{Q}_{\mathrm{L}} \equiv \omega \mathrm{w}_{\mathrm{T}} /\left(\mathrm{P}_{\mathrm{DI}}+\mathrm{P}_{\mathrm{DE}}\right) \qquad \qquad \qquad \text{(loaded Q)}\]

    Therefore these Q’s are simply related:

    \[\mathrm{Q}_{\mathrm{L}}^{-1}=\mathrm{Q}_{\mathrm{I}}^{-1}+\mathrm{Q}_{\mathrm{E}}^{-1}\]

    It is QL that corresponds to Δω for coupled resonators (QL = ωo/Δω) .

    For example, by applying Equations (3.5.38–40) to a series RLC resonator, we readily obtain:

    \[Q_{I}=\omega_{0} L / R\]

    \[\mathrm{Q}_{\mathrm{E}}=\omega_{\mathrm{o}} \mathrm{L} / \mathrm{R}_{\mathrm{Th}}\]

    \[Q_{L}=\omega_{0} L /\left(R_{T h}+R\right)\]

    For a parallel RLC resonator the Q’s become:

    \[\mathrm{Q}_{\mathrm{I}}=\omega_{\mathrm{o}} \mathrm{RC}\]

    \[\mathrm{Q}_{\mathrm{E}}=\omega_{\mathrm{O}} \mathrm{R}_{\mathrm{Th}} \mathrm{C}\]

    \[\mathrm{Q}_{\mathrm{L}}=\omega_{\mathrm{o}} \mathrm{CR}_{\mathrm{Th}} \mathrm{R} /\left(\mathrm{R}_{\mathrm{Th}}+\mathrm{R}\right)\]

    Since the source and load resistances are matched for maximum power dissipation at resonance, it follows from Figure 3.5.3 that a critically coupled resonator or matched resonator results when QI = QE. These expressions for Q are in terms of energies stored and power dissipated, and can readily be applied to electromagnetic resonances of cavities or other structures, yielding their bandwidths and conditions for maximum power transfer to loads, as discussed in Section 9.4.


    This page titled 3.5: Two-element circuits and RLC resonators is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by David H. Staelin (MIT OpenCourseWare) via source content that was edited to the style and standards of the LibreTexts platform; a detailed edit history is available upon request.