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Physics LibreTexts

11.1: Introduction

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Consider a plane wave propagating along the z-direction in vacuum, and polarized with its electric vector along the x-axis: its magnetic field vector must be directed along the y-axis. Now introduce two infinitely conducting metal planes which block off all of space except the region between x= +a and x= -a, see Figure (11.1.1). The boundary conditions at x= ±a that must be satisfied by the electric and magnetic fields are

  1. the tangential components of E must be zero;
  2. the normal component of H must be zero.

This latter condition is a consequence of the Maxwell equation

div(B)=0

which requires the normal component of B to be continuous through an interface, coupled with the requirement that both the electric and magnetic fields are zero inside a perfect conductor: recall from Chapter(10) that in the limit of infinite conductivity the skin depth of a metal goes to zero. Notice that the above two boundary conditions are satisfied by the plane wave. The plane wave solutions of Maxwell’s equations

Ex=E0exp(i[kzωt]),Hy=H0exp(i[kzωt]),

can be used to describe the propagation of electromagnetic energy between two conducting planes. Energy is transported at the speed of light just as it is for a plane wave in free space. Notice that if it is attempted to close in the radiation with conducting planes at y= ±b the boundary conditions Ex = 0 and Hy = 0 cannot be satisfied on the planes y= ±b. Waves can be transmitted through such hollow pipes but the radiation bounces from wall to wall in a complex pattern that will be studied later. It will be shown that waves cannot be transmitted through a hollow pipe if the frequency is too low; there exists a lower frequency cut-off. However, a pair of parallel conducting planes unbounded in one transverse direction can transmit waves at all frequencies. In practice infinite planes are inconvenient, so one uses either strip-lines or co-axial cables, see Figures (11.1.2) and (11.2.3).

Figure 11.1.PNG
Figure 11.1.1: A plane wave propagating between two perfectly conducting planes. Ex=E0exp(i[kzωt]),Hy=(E0/Z0)exp(i[kzωt]).
Figure 11.2.PNG
Figure 11.1.2: A strip-line. Ex=E0,V=E0d.Hy=E0/Z0,I=wJs=w(E0/Z0)

This page titled 11.1: Introduction is shared under a CC BY 4.0 license and was authored, remixed, and/or curated by John F. Cochran and Bretislav Heinrich.

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